do while循环不能有两个cin语句？ [英] do while loops can't have two cin statements?

问题描述

我只是遵循一个简单的c ++教程do / while循环，我似乎已经复制了本教程中写的是什么，但我不会得到相同的结果。这是我的代码：

I'm just following a simple c++ tutorial on do/while loops and i seem to have copied exactly what was written in the tutorial but i'm not yielding the same results. This is my code:

int main()
{
    int c=0;
    int i=0;
    int str;
    do
    {
        cout << "Enter a num: \n";
        cin >> i;
        c = c + i;
        cout << "Do you wan't to enter another num? y/n: \n";
        cin >> str;

    } while (c < 15);

    cout << "The sum of the numbers are: " << c << endl;


    system("pause");
    return (0);
}

现在，在1次迭代之后，循环运行时不需要输入再次，并且只计算与我的第一个初始输入的和。
然而，如果我删除第二对cout / cin语句，程序工作正常..

Right now, after 1 iteration, the loop just runs without asking for my inputs again and only calculating the sum with my first initial input for i. However if i remove the second pair of cout/cin statements, the program works fine..

有人可能发现我的错误吗？

can someone spot my error please? thank you!

推荐答案

如果更改

int str;

到

char str;

您的循环按照您的意图工作（在Visual Studio 2010中测试）。

虽然，你也应该检查 str =='n'，因为他们告诉你他们已经完成了。

Your loop works as you seem to intend (tested in Visual Studio 2010).
Although, you should also probably check for str == 'n', since they told you that they were done.

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