如何复制包含“\0”字符的数据 [英] How could I copy data that contain '\0' character

问题描述

我正在尝试复制\0的数据。我使用C ++。
当研究结果是否定的，我决定写我自己的命令来将数据从一个char *复制到另一个char *。但它不返回想要的结果！
我的尝试如下：

I'm trying to copy data that conatin '\0'. I'm using C++ . When the result of the research was negative, I decide to write my own fonction to copy data from one char* to another char*. But it doesn't return the wanted result ! My attempt is the following :

#include <iostream>


char* my_strcpy( char* arr_out,  char* arr_in, int bloc )
{
 char* pc= arr_out;

 for(size_t i=0;i<bloc;++i)     
 {

        *arr_out++ = *arr_in++ ;
 }

 *arr_out = '\0';
 return pc;
}

int main()
{
    char * out= new char[20];
    my_strcpy(out,"12345aa\0aaaaa  AA",20);
    std::cout<<"output data: "<< out << std::endl;
    std::cout<< "the length of my output data: " << strlen(out)<<std::endl;
    system("pause");
    return 0;
}

结果如下：

the result is here:

我不明白我的代码有什么问题。

I don't understand what is wrong with my code.

感谢您提前寻求协助。

推荐答案

当你写 char * 到 cout 时，c $ c> my_strcpy 或calc的长度与 strlen 他们停止在 \0 。顺便说一下，您可以使用 memcpy 复制 char 的块，而不管 \ 0 。

Your my_strcpy is working fine, when you write a char* to cout or calc it's length with strlen they stop at \0 as per C string behaviour. By the way, you can use memcpy to copy a block of char regardless of \0.

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