OpenCV图像大小比较到matlab [英] OpenCV image resize comparison to matlab

问题描述

这里是我的函数

  int * Utilities :: MatlabImresize（int * channel，int width，int height，double scale ）
 {
 cv :: Mat src（width，height，CV_32F）; 
 for（int i = 0; i  {
 src.at< float>（i）= channel [i] 
} 
 cv :: Mat dst; 
 cv :: resize（src，dst，cv :: Size（），0.5，0.5，cv :: INTER_CUBIC）; 
 ofstream myfile; 
 myfile.open（C：\\Users\\gdarmon\\Desktop\\OpenCV_CR.txt）; 
 myfile<< dst; 
 myfile.close（）; 
 
 return NULL; 
} 
  

正如我上一个问题 imresize - 试图理解双三次插值
我已经重新编译openCV与 - 0.5f 而不是 -0.75f

输入是相同的，我想我使用resize（）函数错误...可以帮助吗？

matlab代码只是

  Gr = imresize（Gr，0,5）; 
  

解决方案

更改为OpenCV只会使插值内核公式匹配。它不启用抗锯齿。这里的结果将与

匹配

  imresize（A，scale，'bicubic'，'AntiAliasing'，false）
 
 
 
 
要匹配默认值，您需要进一步修改内核，使其更宽。
 
here is my function 
int* Utilities::MatlabImresize(int* channel,int width, int height, double scale)
{
    cv::Mat src(width, height, CV_32F);
    for (int i = 0; i < width * height; ++i)
    {
        src.at<float>(i) = channel[i];      
    }
    cv::Mat dst;
    cv::resize(src, dst, cv::Size(), 0.5, 0.5,cv::INTER_CUBIC);
    ofstream myfile;
    myfile.open("C:\\Users\\gdarmon\\Desktop\\OpenCV_CR.txt");
    myfile << dst;
    myfile.close();

    return NULL;
}
As discussed in my previous question imresize - trying to understand the bicubic interpolation
I have recompiled openCV with -0.5f instead of -0.75f

however I still get different results although the input is the same, I guess i'm using resize() function wrong... can you please help?

the matlab code is just
Gr = imresize(Gr, 0,5);

解决方案
That change to OpenCV only makes the interpolation kernels' formulas match.  It does not enable anti-aliasing. The result here will match with 
imresize(A,scale,'bicubic','AntiAliasing',false)
To match the default, you'd need to further modify the kernel, making it broader.

                        
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