规则从文本文档中提取键+短语 [英] rule to extract key+phrases from a text document
问题描述
我想从文档中提取关键短语:某些KEY短语END something ... ect。我的规则运行良好,但结果不包含键名称。为了得到一个字符串,应该是什么规则:KEY phrase。谢谢您的建议。
I want to extract the key phrases from the document: "something KEY phrase END something ... ect". My rule works well but the result does not contain of key name. What should be the rule in order to get a string: "KEY phrase". Thank you for the advice.
std::vector<std::string> doc;
bool r = qi::phrase_parse(first,last,
( qi::omit[*(qi::char_-"KEY")]
>> qi::lexeme[ "KEY"
>> *(qi::char_-"KEY" -"END")] ) % "END"
, qi::space, doc);
推荐答案
qi :: lit ...)
不合成属性。
qi :: string(...) code>。
qi::string(...)
does.
使用qi :: string(KEY)替换KEY可能。 (很难不知道
doc
的类型)
Replace "KEY"
with qi::string("KEY"), likely. (hard to tell without knowing the type of doc
)
bool r = qi::phrase_parse(first,last,
( qi::omit[*(qi::char_-"KEY")]
>> qi::lexeme[ qi::string("KEY")
>> *(qi::char_-"KEY" -"END")] ) % "END"
, qi::space, doc);
奖金另请参阅 寻求[]
解析器指令 <从圣灵库/ STRONG>
BONUS See also seek[]
parser directive from the Spirit Repository:
求[]
解析器指令跳过所有输入,直至主题解析器的比赛。
The
seek[]
parser-directive skips all input until the subject parser matches.
下面就是我想要做的:
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/repository/include/qi_seek.hpp>
namespace qi = boost::spirit::qi;
namespace qr = boost::spirit::repository::qi;
extern std::string const sample; // below
int main() {
auto f(sample.begin()), l(sample.end());
std::vector<std::string> phrases;
if (qi::parse(f,l, *qi::as_string[
qr::seek[qi::string("KEY")] >> *(qi::char_ - "END")
], phrases))
{
for (size_t i = 0; i < phrases.size(); ++i)
std::cout << "keyphrase #" << i << ": '" << phrases[i] << "'\n";
}
}
列印:
keyphrase #0: 'KEY@v/0qwJTjgFQwNmose7LiEmAmKpIdK3TPmkCs@'
keyphrase #1: 'KEY@G1TErN1QSSKi17BSnwBKML@'
keyphrase #2: 'KEY@pWhBKmc0sD+o@'
keyphrase #3: 'KEY@pwgjNJ0FvWGRezwi74QdIQdmUuKVyquWuvXz4tBOXqMMqco@'
keyphrase #4: 'KEY@aJ3QUfLh3AqfKyxcUSiDbanZmCNGza6jb6pZ@'
keyphrase #5: 'KEY@bYJzitZUyXlgPA009qBpleHIJ9uJUSdJO78iisUgHkoqUpf+oXZQF9X/7v2fikgemCD@'
此答案中的注释中包含示例数据:/ here /
Sample data included in a comment in this answer: /here/
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