从日数计算日期？ [英] Calculating the date from day-number?

问题描述

如何从C ++中的日数计算日期？我不需要你写整个代码，我只是不能弄清楚数学来计算月份和日期！

How would one go about calculating a date from a day-number in C++? I don't require you to write the whole code, I just can't figure out the maths to calculate the month and the day-of-month!

示例：

input: 1
output: 01/01/2012

input: 10
output: 01/10/2012

input: 365
output: 12/31/2012

它总是使用当前年份，如果他们超过365，我会返回0.没有必要闰年检测。

It would always use the current year, if they exceeded 365, I would return 0. There is no need for a leap-year detection.

推荐答案

使用日期calc库如eg精致的 Boost Date_Time 图书库，它将成为

Use a date calc library as e.g. the fine Boost Date_Time library with which this becomes

using namespace boost::gregorian;
date d(2012,Jan,1);                     // or one of the other constructors
date d2 = d + days(365);                // or your other offsets

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