C ++“命名空间范围” [英] C++ "namespace scope"

问题描述

C ++规范（ http：// www.open-std.org/jtc1/sc22/wg21/docs/papers/2011/n3242.pdf ，第7.5.4节）指出

链接规定只能在命名空间范围内发生

命名空间范围到底是什么意思？这是否意味着链接规范，如 externC不能在全局范围内，只能在命名空间中？

这意味着 externC应该只在命名空间范围（不是类范围，块范围等）。不在命名空间，但在全局范围 - 在全局命名空间范围。

bb
$ b由
表示的潜在范围是一个original-namespace-name是由每个
命名空间所建立的声明区域的连接，在与原始命名空间名称相同的声明性区域中的定义。

The C++ spec (http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2011/n3242.pdf, section 7.5.4) states that

A linkage-specification shall occur only in namespace scope

What exactly does "namespace scope" mean? Does this mean that a linkage-specification, such as extern "C" can't be in global scope, only in a namespace?
What exactly does "namespace scope" mean?

解决方案

It means, that extern "C" should be only in namespace-scope (not class-scope, block-scope etc.) Something, that is not in namespace, but is in global scope - is in global namespace scope.

The potential scope denoted by an original-namespace-name is the concatenation of the declarative regions established by each of the namespace-definitions in the same declarative region with that original-namespace-name.

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