C ++指针 - 这里有什么值？ [英] C++ pointers - What values are held here?

问题描述

如果我有以下指针变量声明：

int * a;

int ** c;

关于类型和每个值将包含的值如下：

a 的类型为 int * ，并且将保存一个内存地址

* a 类型为 int ，并且将保存指针指向的变量的值

c int ** ，并将保留

c * 的类型为 int * 将保存其指向的指针的内存地址

c ** 类型 int ，并且假设指针 c 指向指针 b b 指向变量 a ，这里，保持的值将是变量 a c>

这样是正确的，除了 c 确定吗？

谢谢。

解决方案

  int * a; 
 int ** c; 
  

您对 a 正确。更常见的是 a 持有指向int 的指针。

c 的类型为 int ** ，并且将保存一个指向int 。





* c int * ，并且将保存指向int 的指针。

** c 的类型为 int ，并且将保存一个整数值。您对 c 指向 b 和 b 指向 > cdecl 一些帮助。 ：）

If I have the following pointer variable declarations:

int *a;
int **c;

Regarding to the type and what values each will hold, will it be as follows:

a is of type int*, and will hold a memory address

*a is of type int, and will hold the value of the variable the pointer is pointing to

c is of type int**, and will hold ?????????????????????

c* is of type int*, and will hold the memory address of the pointer it is pointing at

c** is of type int, and assuming that pointer c is pointing to pointer b, and pointer b is pointing to variable a, here, the value held will be the value of the variable a

Is it correct this way, except c which I'm not sure about?

Thanks.

解决方案

int *a;
int **c;

You are correct about a. It is more common to say a holds a pointer to int.

c is of type int** and will hold a pointer to a pointer to int.

*c is of type int*, and will hold a pointer to int.

**c is of type int, and will hold an integer value. You are correct about c pointing to b and b pointing to a.

See cdecl for some help. :)

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