我想告诉VC ++编译器编译所有代码。可以做吗？ [英] I want tell the VC++ Compiler to compile all code. Can it be done?

问题描述

我使用VS2005 VC ++非托管C ++。我有VSTS，我试图使用代码覆盖工具来完成关于单元测试的两件事：

I am using VS2005 VC++ for unmanaged C++. I have VSTS and am trying to use the code coverage tool to accomplish two things with regards to unit tests:

1. 查看我的引用


2. 查看我的测试代码（如果有）的方法未经过单元测试。

设置VSTS代码覆盖率工具（请参阅链接文本）和完成任务＃1是直接。然而＃2对我来说是一个惊人的挑战。这里是我的测试代码。

Setting up the VSTS code coverage tool (see the link text) and accomplishing task #1 was straightforward. However #2 has been a surprising challenge for me. Here is my test code.

class CodeCoverageTarget
{
public:
    std::string ThisMethodRuns() {
         return "Running";
    }

    std::string ThisMethodDoesNotRun() {
        return "Not Running";
    }
};



#include <iostream>
#include "CodeCoverageTarget.h"
using namespace std;
int main()

{
    CodeCoverageTarget cct; 
    cout<<cct.ThisMethodRuns()<<endl;
}

当上述两个方法都定义在类中时，编译器自动消除ThisMethodDoesNotRun （）从obj文件。如果我将它的定义移出类，那么它被包括在obj文件中，代码覆盖工具显示它根本没有被执行。在大多数情况下，我希望编译器为我执行这种消除，但对于代码覆盖工具，它会失去很大一部分的价值（例如找到未经测试的方法）。我已经尝试了一些事情告诉编译器停止为我聪明，编译所有的东西，但我陷入困境。这将是很好，如果代码覆盖工具补偿这（我想通过扫描源和匹配它与链接器输出），但我没有找到任何建议，它有一个特殊的模式打开。我完全缺少一些简单的在这里或者这是不可能用VC ++编译器+ VSTS代码覆盖工具？

When both methods are defined within the class as above the compiler automatically eliminates the ThisMethodDoesNotRun() from the obj file. If I move it's definition outside the class then it is included in the obj file and the code coverage tool shows it has not been exercised at all. Under most circumstances I want the compiler to do this elimination for me but for the code coverage tool it defeats a significant portion of the value (e.g. finding untested methods). I have tried a number of things to tell the compiler to stop being smart for me and compile everything but I am stumped. It would be nice if the code coverage tool compensated for this (I suppose by scanning the source and matching it up with the linker output) but I didn't find anything to suggest it has a special mode to be turned on. Am I totally missing something simple here or is this not possible with the VC++ compiler + VSTS code coverage tool?

提前感谢
KGB

Thanks in advance, KGB

推荐答案

确保您的功能不被丢弃的方式是导出它们。您可以添加 __ declspec（ dllexport） 到你的函数声明。最好将其封装在C预处理器宏中，以便可以将其关闭，因为它是特定于编译器的，并且您可能不希望所有构建都导出符号。导出功能的另一种方法是创建 .DEF 文件。

One way to ensure your functions are not discarded is to export them. You can do this by adding __declspec(dllexport) to your function declarations. It is best to wrap this in a C preprocessor macro so that you can turn it off, since it is compiler-specific and you might not want all of your builds to export symbols. Another way to export functions is to create a .DEF file.

如果内联是问题，您也可能成功了 __ declspec（noinline） 。

If inlining is the problem, you might also have success with __declspec(noinline).

您的代码是否在静态库中，然后编译为测试EXE / DLL？链接器将自动丢弃静态库中未引用的对象文件。示例：如果静态库包含 a.obj 和 b.obj 和您链接的EXE / DLL它引入了来自 b.obj 但不是 a.obj 的引用符号，然后 a.obj 将不会链接到可执行文件或DLL。但是，在重新阅读您的说明后，这听起来不像这里发生了。

Is your code in a static library which is then compiled into a test EXE/DLL? The linker will automatically discard unreferenced object files that are in static libraries. Example: if the static library contains a.obj and b.obj and the EXE/DLL that you're linking it into references symbols from b.obj but not a.obj, then the contents of a.obj will not be linked into the executable or DLL. However, after re-reading your description it doesn't sound like that's what's happening here.

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