C ++打印出限制字数 [英] C++ print out limit number of words

问题描述

我是C ++的初学者，我不知道该怎么做。
我想写一个包含文本行的代码。例如。 你好stackoverflow是一个很好的网站

I'm beginner to C++ and I wonder how to do this. I want to write a code which take in a text line. E.g. "Hello stackoverflow is a really good site"

从输出我只想打印出前三个字，跳过其余的。

From the output I want only to print out the first three words and skip the rest.

输出我想要的：Hello stackoverflow is

Output I want: "Hello stackoverflow is"

如果是Java，分裂（）。至于C ++我真的不知道。它们是什么类似的或是什么是C ++的方法？

If it was Java I would've used the string split(). As for C++ I don't really know. Is their any similar or what is the approach for C++?

推荐答案

但不检测行尾。

The operator >> breaks a stream into words.
But does not detect end of line.

你能做的是读一行然后得到该行的前三个字：

What you can do is read a line then get the first three words from that line:

#include <string>
#include <iostream>
#include <sstream>

int main()
{
    std::string line;
    // Read a line.
    // If it succeeds then loop is entered. So this loop will read a file.
    while(std::getline(std::cin,line))
    {
        std::string word1;
        std::string word2;
        std::string word3;

        // Get the first three words from the line.
        std::stringstream linestream(line);
        linestream >> word1 >> word2 >> word3;
    }

    // Expanding to show how to use with a normal string:
    // In a loop context.
    std::string       test("Hello stackoverflow is a really good site!");
    std::stringstream testStream(test);
    for(int loop=0;loop < 3;++loop)
    {
        std::string     word;
        testStream >> word;
        std::cout << "Got(" << word << ")\n";
    }

}

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