无法删除动态分配的多维数组 [英] Can't delete dynamically allocated multidimensional array

查看:215
本文介绍了无法删除动态分配的多维数组的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我无法删除动态生成的数组。有我如何创建它们:

I can't delete the dynamically generated arrays. There is how I create them:

template <typename T>
T **AllocateDynamic2DArray(int nRows, int nCols){
      T **dynamicArray;

      dynamicArray = new T*[nRows];
      for( int i = 0 ; i < nRows ; i++ ){
        dynamicArray[i] = new T[nCols];
        for ( int j=0; j<nCols;j++){
                dynamicArray[i][j]= 0;
            }
        }
      return dynamicArray;
}

我用一个初始化一个二维数组:

And I initialize a 2D array using:

long double** h = AllocateDynamic2DArray<long double>(KrylovDim+1,KrylovDim);

我无法删除它。以下是我尝试的变体:

I can't delete it. Here are the variations that I've tried:

delete[] h;

并且它提供错误:不能删除不是指针的对象 / p>

and it gives the error: "cannot delete objects that are not pointers" when I apply this:

   for (int qq=0; qq < KrylovDim+1; qq++){
        for (int ww=0; ww < KrylovDim; ww++){
            delete [] h[qq][ww];
        }
        delete [] h[qq];
    }

有没有办法干净的删除?

Is there any way for a clean delete? I'm using visual studio 2010 if it helps.

推荐答案

请尝试以下操作:

for (int qq=0; qq < KrylovDim + 1; qq++)
{
    delete [] h[qq];
}
delete [] h;

所以基本上你正在做相反的分配过程

So basically you are doing the reverse of the allocation process

for( int i = 0 ; i < nRows ; i++ ){
    dynamicArray[i] = new T[nCols]; // Instead of allocating now delete !

这篇关于无法删除动态分配的多维数组的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆