尝试从ASCII文件中读取行使用C ++，Ubuntu和Mac ...？ [英] Trying to read lines from an ASCII file using C++ , Ubuntu vs Mac...?

问题描述

我有一个ASCII文件（students.txt），如下所示（忽略空行，它们是我对此格式工具不熟悉的工具）：

  stella 10 4.4 ... 
 peter 1.1 5 ... 
  

也就是说，每一行都以一个名称开头，后跟一个或多个数字。

下面的代码片段是一行一行地读取的，将名称读入字符串，并将数字转换为双精度，依次打印这些。当我在Ubuntu上运行它时，它运行正常，我得到

  stella 10 4.4 
 peter 1.1 5 $ b $但是，当我在Mac上运行它时，我得到以下结果：
 
 
 
 
 
 
 $ b b $ b 
  stella 10 4.4 
 ter 1.1 5 
  
 
 $ b b 
但是，当我将peter改为speter时，它运行正常...：
  stella 10 4.4 
 speter 1.1 5 
  
任何想法...？
  #include< iostream> 
 #include< fstream> 
 #include< string> 
 
 using namespace std; 
 
 
 int main（）{
 
 ifstream intile（students.txt）; 
 string name; 
 double x; 
 
 while（！infile.eof（））{
 infile>>名称; 
 cout<<名称<< ''; 
 while（infile>> x）{
 cout<< x<< ''; 
} 
 cout<< endl; 
 if（！infile.eof（））
 infile.clear（）; 
} 
 
 return 0; 
} 
  
 
 
解决方案
成行，通常最容易通过行读取它们，然后将它们分成组件：
  std :: string line; 
 
 std :: string name; 
 std :: vector< double>值; 
 
 while（std :: getline（infile，line））{
 std :: isTringstream buffer（line）; 
 double temp; 
 
 buffer>>名称; 
 while（buffer>> temp）
 values.push_back（temp）; 
} 
  
 
I have an ASCII file (students.txt) that looks as follows (Ignore empty lines, they're an artifact of my unfamiliarity with this formatting tool):
stella 10 4.4 ...
peter 1.1 5 ...
That is, each line starts with a name, followed by one or more numbers.

The code snippet below is meant to read this file line by line, reading the name into a string and the numbers into a double, printing each of these in turn. When I run this on Ubuntu, it works fine and I get
stella 10 4.4
peter 1.1 5
However, when I run it on a Mac, I get the following:
stella 10 4.4
ter 1.1 5
When I change 'peter' to 'speter', however, it works fine...:
stella 10 4.4
speter 1.1 5
Any thoughts...?
#include <iostream>
#include <fstream>
#include <string>

using namespace std;


int main() {

  ifstream infile("students.txt");
  string name;
  double x;

  while ( !infile.eof() ) {
    infile >> name;
    cout << name << ' ';
    while ( infile >> x ){
      cout << x << ' ';
    }
    cout << endl;
    if (! infile.eof() )
      infile.clear();
  }

  return 0;
}

解决方案
When the input starts out divided into lines, it's usually easiest to read it by lines, then split those into the component pieces:
std::string line;

std::string name;
std::vector<double> values;

while (std::getline(infile, line)) {
    std::istringstream buffer(line);
    double temp;

    buffer >> name;
    while (buffer >> temp)
        values.push_back(temp);
}


                        
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