如何使用整数作为键/名称将成员添加到rapidjson文档? [英] How can I add members to a rapidjson document using integers as the key/name?
问题描述
我使用for循环,并希望使用迭代器,i,作为键/名称当我添加一个成员到文档。例如,我想让文档看起来像这样:
{1:123.321,2:456.654}
这是我到目前为止所尝试的。
1。将i转换为const char *
rapidjson :: Value newDouble(6);
for(int i = 0; i< laserScan.size(); i ++){
newDouble.SetDouble(laserScan [i]);
const char * index = std :: to_string(i).c_str();
d.AddMember(index,newDouble,d.GetAllocator());
}
这会产生编译器错误,告诉我AddMember只能接受类型rapidjson的参数:: GenericValue&:
错误:没有匹配的函数调用'rapidjson :: GenericDocument< rapidjson :: UTF8& > :: AddMember(const char *& rapidjson :: Value& rapidjson :: MemoryPoolAllocator<&)'
d.AddMember(index,newDouble,d.GetAllocator());将此名称 - 值对添加到JSON字符串
2。使用rapidjson类型将i转换为字符串
rapidjson :: Value newDouble(6),newStringIndex
for(int i = 0; i< laserScan.size(); i ++){
newDouble.SetDouble(laserScan [i]);
const char * index = std :: to_string(i).c_str();
size =(rapidjson :: SizeType)std :: strlen(index);
newStringIndexSetString(rapidjson :: StringRef(index,size));
d.AddMember(newStringIndex,newDouble,d.GetAllocator());
}
这会从Writer类抛出以下运行时错误:
断言`!hasRoot_'失败。
为什么我困惑
$
d.AddMember( 1,newDouble,d.GetAllocator());
当我尝试它时,这是工作,但我不知道为什么将整数转换为const char *不会。
我发现了一个解决方法。而不是使所有的键整数,我只是添加关键索引与相应的值是所有索引的数组。然后我添加了另一个名为data的数组,其中包含所有数据的数组:
rapidjson :: Document document;
rapidjson :: Document :: AllocatorType& allocator = document.GetAllocator();
rapidjson :: Value dataArray(rapidjson :: kArrayType),;
for(int i = 0; i dataArray.PushBack(rapidjson :: Value()。SetDouble(laserScan [i]),allocator );
}
document.AddMember(data,dataArrary,allocator);
I'm using a for loop and want to use the iterator, i, as the key/name when I add a member to the document. For example I want the document to look like this:
{"1":"123.321","2":"456.654"}
Here is what I have tried so far.
1. Converting i to a const char*
rapidjson::Value newDouble(6);
for(int i = 0;i<laserScan.size();i++){
newDouble.SetDouble(laserScan[i]);
const char* index = std::to_string(i).c_str();
d.AddMember(index,newDouble,d.GetAllocator());
}
This generates a compiler error telling me that AddMember can only take arguments of type rapidjson::GenericValue&:
error: no matching function for call to ‘rapidjson::GenericDocument<rapidjson::UTF8<> >::AddMember(const char*&, rapidjson::Value&, rapidjson::MemoryPoolAllocator<>&)’
d.AddMember(index,newDouble,d.GetAllocator());//add this name-value pair to the JSON string
2. Converting i to a string using rapidjson types
rapidjson::Value newDouble(6), newStringIndex(5);
for(int i = 0;i<laserScan.size();i++){
newDouble.SetDouble(laserScan[i]);
const char* index = std::to_string(i).c_str();
size = (rapidjson::SizeType)std::strlen(index);
newStringIndex.SetString(rapidjson::StringRef(index,size));
d.AddMember(newStringIndex,newDouble,d.GetAllocator());
}
This throws the following run-time error from Writer class:
Assertion `!hasRoot_' failed.
Why I'm Confused
Shouldn't solution #1 be the same thing as doing the following?
d.AddMember("1",newDouble,d.GetAllocator());
This works when I try it, but I can't figure out why converting an integer to a const char* won't.
I found a workaround. Instead of making all the keys integers, I just added the key "indices" with the corresponding value being an array of all the indices. Then I added another array called "data" which contained an array of all the data:
rapidjson::Document document;
rapidjson::Document::AllocatorType& allocator = document.GetAllocator();
rapidjson::Value dataArray(rapidjson::kArrayType), ;
for(int i = 0;i<laserScan.size();i++){
dataArray.PushBack(rapidjson::Value().SetDouble(laserScan[i]),allocator);
}
document.AddMember("data",dataArrary,allocator);
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