C ++ Assertion在运行时向量上失败表达式：向量下标超出范围 [英] C++ Assertion Failed on vector at runtime Expression: vector subscript out of range

问题描述

im gettin这真是讨厌的错误信息。我知道Im只是新的，但它似乎是我能找出的事情的类型。任何人都可以告诉我哪里出错了？

im gettin this really annoying error message. I know Im only new to this but it seems the type of thing I could figure out. Can anyone show me where im going wrong please?

运行时的消息是：
Debug Assertion Failed！
程序：
....
文件：c：\program files\microsoft visual studio 10.0 \vc\include\vector
Line：932
表达式：向量下标超出范围

，代码为

#include "VectorIntStorage.h"
#include <iostream>
#include <fstream>
#include <string>
#include <vector>
#include <algorithm>

using namespace std;

void VectorIntStorage::Read(istream& r)
{
    char c[13];
    r >> c;
    r >> NumberOfInts; //gets number of ints for vector

    //numberVector = new std::vector<int> numberVector;

    for(int i = 0; i < NumberOfInts; i++)
    {
        r >> numberVector[i];
        cout << numberVector[i] << endl;

        if(_sortRead) //true
        {
            for(int k = 0; k < i; k++)
            {
                if(numberVector[i] < numberVector[k])
                {
                    int temp = numberVector[k];
                    numberVector[k] = numberVector[i];
                    numberVector[i] = temp;
                }
            }
        }
    }
}

void VectorIntStorage::Write(ostream& w)
{
    for(int i = 0; i < NumberOfInts; i++)
    {
        w << numberVector[i] << endl;
        cout << numberVector[i] << endl;
    }
}

void VectorIntStorage::sortStd()
{
    sort(numberVector.begin(), numberVector.end());
}

void VectorIntStorage::sortOwn()
{
    quickSort(0, NumberOfInts - 1);
}

void VectorIntStorage::setReadSort(bool sort)
{
    _sortRead = sort;
}

void VectorIntStorage::quickSort(int left, int right)
{
     int i = left, j = right;
      int tmp;
      int pivot = numberVector[(left + right) / 2];

      while (i <= j)
      {
            while (numberVector[i] < pivot)
                  i++;
            while (numberVector[j] > pivot)
                  j--;
            if (i <= j) 
            {
                  tmp = numberVector[i];
                  numberVector[i] = numberVector[j];
                  numberVector[j] = tmp;
                  i++;
                  j--;
            }
      }

      if (left < j)
      {
            quickSort(left, j);
      }
      if (i < right)
      {
            quickSort(i, right);
      }
}

VectorIntStorage::VectorIntStorage(const VectorIntStorage& copying)
{
    //int *duplicate = new int[(copying.NumberOfInts)];
    //vector<int> *duplicate = new vector<int>;

    //std::copy(numberVector.begin(), numberVector.end(), duplicate);
    //numberVector = duplicate;
    //NumberOfInts = copying.NumberOfInts;
}

VectorIntStorage::VectorIntStorage(void)
{
}


VectorIntStorage::~VectorIntStorage(void)
{
}

推荐答案

没有足够的信息可以肯定地说，但我怀疑失败的线是 r>> numberVector [i] 。我想你是说 int j; r> j; numberVector.push_back（j）;

We don't have enough information to say for sure, but I suspect the failing line is r >> numberVector[i]. I suppose you meant to say int j; r >> j; numberVector.push_back(j);

问题正是错误消息所说：你的向量下标（ i ）超出范围。具体来说，你从不增加你的向量的大小，所以它总是大小为0.因此，任何使用 operator [] 将引用一个超出范围元素。

The problem is precisely what the error message says: your vector subscript (i) is out of range. Specifically, you never increase the size of your vector, so it is always of size 0. Thus, any use of operator[] is going to reference an out-of-range element.

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