“空值不应被忽略，因为它应该是” - Qt / C ++ [英] "void value not ignored as it ought to be" - Qt/C++

问题描述

I have this simple "interface" for some plugins I want to develop, it looks like:

还有一些实现接口的类：

class TestPluginBase : public QObject { Q_OBJECT public: TestPluginBase(); qint64 returnType(){return PluginType;} protected: qint64 PluginType; };

And some other classes which implement the "interface" like:

然后我有另一个函数，假设加载不同的插件：

class TestPluginONE : public TestPluginBase { public: TestPluginONE() {this->PluginType =1;} qint64 returnType() {return this->PluginType;} };

Then I have another function which suppose to load different plugins:

但是当构建它时，我得到 void value not忽略，因为它应该是和Qt creator说实例化从行我做我的演员...不能弄清楚我做错了什么...任何帮助/ c> TestPluginBase（）{this-> TestPluginBase（）{

qint64 TestPluginManager::loadPlugin(QObject *_plugin) { TestPluginBase *Plugin = qobject_cast<TestPluginBase *>(_plugin); if ( !Plugin ) return 0; emit sigPluginLoaded(Plugin); return Plugin->returnType(); }

推荐答案

> PluginType = 0;} ，代码正在编译没有错误。解决我的问题，但不知道为什么。

modified the constructor in my "interface" to TestPluginBase() {this->PluginType =0;} and the code is compiling with no error..solved my problem but don't know why.

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