从派生作用域调用函数 [英] Calling function from derived scope

问题描述

我有一些代码似乎与此类似：

I have some code which seems similair to this:

#include <iostream>

class Base {
public:
    void test() {
        std::cout << "Base::test()" << std::endl; 
    }

    void test2() {
        test();
    }
};

class Derived : public Base {
public:
    void test() {
        std::cout << "Derived::test()" << std::endl;
    }
};

int main() {
    Derived d;
    d.test2();
    return 0;
}

现在输出ofcourse Base :: test ，但我希望它输出 Derived :: test（） 而不使用虚函数调用和使用不同的符号为函数重载调用： Derived :: test 。

Now this outputs ofcourse Base::test(), however I want it to output Derived::test() without making use of virtual function calls and using an different notation for the function overload called: Derived::test.

有人知道这是否可能实现 c>

Does someone know if this is possible to achieve?

推荐答案

template<typename D>
class Base {
public:
    void test() {
        std::cout << "Base::test()" << std::endl;
    }

    void test2() {
        (static_cast<D*>(this))->test();
    }
};

然后，您将从 Derived code> Base 而不只是 Base ：

Then, you would derive Derived from Base<Derived> instead of just Base:

class Derived : public Base<Derived> {
//                     ^^^^^^^^^^^^^
//                     This is the only change required in Derived
public:
    void test() {
        std::cout << "Derived::test()" << std::endl;
    }
};

这是一个 生活示例 。

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