使用相同的值填充数组，循环到复位值 [英] Filling an array with the same value, looping to reset values

问题描述

我正在编写一个编程项目（mancala），并且在编写数组时遇到困难。我需要写一个数组，填充所有的板仓，值为4，然后将两个bin重置为0.到目前为止我只有

I'm working on a programming project (mancala) and have gotten stuck when writing an array. I need to write an array that fills all board bins with the value of four, and then resets two bins to 0. So far I only have

{

    int i;
    int beadArray[MAX] = {4};

    for (i = 0; i < MAX; i++)
    {
           beadArray[i] = -1;
    }

    for (i = 0; i < MAX; i++)
    {
            cout<<i<<"\t";

    }

推荐答案

你指定要使用循环来填充索引6和13？如果你只填充两个值，则不需要循环。

Why do you specify that you want to use a loop to fill in indices 6 and 13? If you're only filling in two values a loop is not necessary.

由于这只是一个mancala游戏，如果你不需要使用大于255（单个字节可以容纳的最大值），那么可以使用unsigned char数组和memset。

Since this is only for a mancala game, if you don't need to use numbers larger than 255 (the maximum value a single byte can hold) then you can use an unsigned char array and memset.

char beadArray[MAX];
memset( beadArray, 4, sizeof(beadArray));
beadArray[6] = beadArray[13] = 0;
for( int i = 0; i < sizeof(beadArray); i++)
    cout << beadArray[i] << "\t";

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