从字符数组解析文件名 [英] Parsing file names from a character array

问题描述

我道歉，如果这之前已被问过，但我试图解析一个字符数组，我可以获得文件名。

I apologize if this has been asked before but I am trying to parse an array of characters in away I can obtain filenames.

这里是一个字符的例子数组我最后复制。

Here is an example of the character array I end up copying in.

picture1.bmp   file2.txt   random.wtf   dance.png

请注意，每个文件名之间有3个空格。

Notice that there are 3 spaces between each filename.

1. 假设我们从第一个字符开始，直到我们到达一个空格。


2. 将所有空间复制到索引为0的数组中。


3. 跳过2个空格（以遍历3个空格间隔）。


4. 直到我们击中一个空格，然后将其复制到数组索引1中。

1. Assuming we start at the first character, advance until we reach a space.
2. Copy everything up to that space into an array at index 0.
3. Skip 2 spaces (to traverse the 3 space gap).
4. Go until we hit a space and then copy that into array index 1.

我可以做一个hack工作

I could do a hack job of this, just curious as to how some of the more advanced programmers would do this as I am here to learn.

推荐答案

std::istringstream iss(the_array);
std::string f1, f2, f3, f4;
iss >> f1 >> f2 >> f3 >> f4;

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