这个代码泄漏内存吗? (引用,新,但不删除) [英] Does this code leak memory? (references, new, but no delete)
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问题描述
Possible Duplicate:
Does using references instead of pointers, resolve memory leaks in C++?
当我提出这个问题时
一个新问题出现,我在这篇文章中提出。
A new question appears and I ask it in this post.
这个代码是否泄漏内存?
Does this code leak memory?
class my_class
{
...
};
my_class& func()
{
my_class* c = new my_class;
return *c;
}
int main()
{
my_class& var1 = func();
// I think there is no memory leak.
return 0;
}
推荐答案
。由 new
创建的所有内容必须由 delete
销毁。在您的代码中有 new
,但没有 delete
。这将立即意味着 new
ed内存泄漏。
Yes, it does leak memory. Everything that was created by new
has to be destroyed by delete
. There's new
in your code, but no delete
. That immediately means that the new
ed memory is leaked.
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