c ++代码通过Visual Studio c + +和Gcc生成不同的输出 [英] c++ code producing different outputs through Visual Studio c++ and Gcc
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问题描述
我有以下C ++程序：
I have the following C++ Program:
//============================================================================
// Name :
// Author : Bryce Sandlund
// Version :
// Copyright :
// Description : Code skeleton
//============================================================================
#include <iostream>
#include <iomanip>
#include <set>
#include <vector>
#include <algorithm>
#include <cmath>
#include <complex>
#include <cstdlib>
#include <sstream>
#include <list>
#include <map>
#include <fstream>
#include <string>
#include <time.h>
#include <queue>
#include <tuple>
#include <functional>
#include <unordered_set>
#include <unordered_map>
#define INF 1000000000
#define all(c) (c).begin(),(c).end()
#define tr(c,i) for(typeof((c).begin()) i = (c).begin(); i != (c).end(); ++i)
#define EP .00001
using namespace std;
typedef pair<int, int> ii;
typedef vector<int> vi;
typedef vector<bool> vb;
typedef vector<vi> vvi;
typedef vector<vb> vvb;
typedef vector<ii> vii;
typedef vector<double> vd;
typedef vector<vd> vvd;
typedef long long LL;
vvi adjList;
unordered_map<string, int> targs;
int add(string &s)
{
if (targs.count(s))
return targs[s];
targs[s] = targs.size();
adjList.push_back(vi());
return targs.size()-1;
}
void connect(int si, int ti)
{
if (si == ti)
return;
for (int i = 0; i < adjList[si].size(); ++i)
{
if (adjList[si][i] == ti)
return;
}
adjList[si].push_back(ti);
}
vi bfs(int s)
{
queue<ii> q;
q.push(ii(s, -1));
vi dist(adjList.size(), INF);
while (!q.empty())
{
int top = q.front().first;
int hops = q.front().second;
q.pop();
if (dist[top] != INF)
continue;
dist[top] = hops;
for (int i = 0; i < adjList[top].size(); ++i)
{
q.push(ii(adjList[top][i], hops+1));
}
}
return dist;
}
int main() {
int caseNum = 1;
cout << "Case " << caseNum << ":" << endl;
string line;
while (getline(cin, line))
{
stringstream ss(line);
string command;
ss >> command;
if (command == "add")
{
string s, t;
ss >> s;
int si = add(s);
if (ss >> t)
{
int ti = add(t);
connect(si, ti);
connect(ti, si);
}
}
else if (command == "connections")
{
string s;
ss >> s;
if (!targs.count(s))
{
cout << "target does not exist" << endl;
continue;
}
int st = targs[s];
if (adjList[st].empty())
{
cout << "no connections" << endl;
}
else
{
vi dist = bfs(st);
vi away(adjList.size(), 0);
int maxd = -1;
for (int i = 0; i < dist.size(); ++i)
{
if (dist[i] == INF || dist[i] == -1)
continue;
++away[dist[i]];
maxd = max(maxd, dist[i]);
}
for (int i = 0; i <= maxd; ++i)
{
cout << i << ": " << away[i] << endl;
}
}
}
else if (command == "associated")
{
string s, t;
ss >> s >> t;
if (!targs.count(s) || !targs.count(t))
{
cout << "target does not exist" << endl;
continue;
}
int si = targs[s], ti = targs[t];
vi dist = bfs(si);
if (dist[ti] == INF)
{
cout << "no" << endl;
}
else
{
cout << "yes " << dist[ti] << endl;
}
}
else
{
adjList.clear();
targs.clear();
cout << "----------" << endl;
cout << "Case " << ++caseNum << ":" << endl;
}
}
cout << "----------" << endl;
return 0;
}
我用这个作为输入：
add a b
add a c
add b d
add e b
add c f
add c g
add f h
add h i
add j k
associated a i
associated i a
associated f k
associated a h
connections a
connections i
add k g
associated a j
connections a
add h a
connections a
associated a h
add m
add n n
connections n
add a n
connections n
在Visual C ++中，代码生成此输出（它在Debug或Release上是这样）：
In Visual C++, the code produces this output (it does so on Debug or Release):
Case 1:
yes: 3
yes: 3
no
yes: 2
0: 2
1: 4
2: 1
3: 1
0: 1
1: 1
2: 1
3: 2
4: 1
5: 2
yes: 3
0: 2
1: 4
2: 2
3: 2
0: 3
1: 5
2: 1
3: 1
yes: 0
no connections
0: 1
1: 3
2: 5
3: 1
4: 1
----------
在gcc g ++上， ：
On gcc g++, it produces this output:
Case 1:
no
no
yes 0
no
0: 2
1: 2
2: 2
3: 1
0: 1
no
0: 2
1: 2
2: 2
3: 1
0: 3
1: 2
2: 2
3: 1
yes 0
----------
任何想法为什么输入和输出将不同的不同的编译器？我不相信我使用任何未定义的行为。
Any ideas why the input and output would be different on the different compilers? I don't believe I am using any undefined behavior.
推荐答案
两个平台是 add 函数。您有：
The cause of the differences in the behavior of the code in the two platforms is the add function. You have:
int add(string &s)
{
if (targs.count(s))
return targs[s];
targs[s] = targs.size();
adjList.push_back(vi());
return targs.size()-1;
}
在该函数中，有问题的行是：
In that function, the problematic line is:
targs[s] = targs.size();
这行很棘手，因为根据赋值操作符的哪一边先求值， 。请注意， targs [s] 涉及更改对象的函数调用。
The line is tricky because depending on which side of the assignment operator gets evaluated first, you get different behavior. Please note that targs[s] involves a function call that changes the object.
您可以更改函数a
int add(string &s)
{
if (targs.count(s))
return targs[s];
int size = targs.size();
targs[s] = size;
adjList.push_back(vi());
return size;
}
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