在释放模式下编译但在调试模式下编译错误 [英] Error compiling in release mode but not in debug mode

问题描述

当我在de 2008的VS 2008年编译一切正常。
当我在发布模式下编译同样的东西不是一切正常。就我可以告诉include目录是相同的，没有其他预处理符号。

When I compile on VS 2008 in deubg mode everything works fine. When I compile the same thing in release mode not everything works. As far as I can tell the include directories are the same and there are no additional preprocessor symbols.

任何帮助？

1> zlib.cpp 1> C：\Program Files
（x86）\ Microsoft Visual Studio
9.0 \VC\include\xutility 419）：错误C2664：
'CryptoPP :: AllocatorWithCleanup :: AllocatorWithCleanup（const
CryptoPP :: AllocatorWithCleanup&）'
：不能从
转换参数1 CryptoPP :: AlchematorWithCleanup'to
'const
CryptoPP :: AllocatorWithCleanup&'
1> with 1> [1>

T = std :: _ Aux_cont 1>] 1>

和1> [1>

T = CryptoPP :: HuffmanDecoder :: CodeInfo
1>] 1>和1> [
1> T = std :: _ Aux_cont 1>

] 1>原因：无法将
从
'CryptoPP :: AllocatorWithCleanup'转换为
'const
CryptoPP :: AllocatorWithCleanup '1>
with 1> [1>

T = CryptoPP :: HuffmanDecoder :: CodeInfo
1>] 1>和1> [
1> T = std :: _ Aux_cont 1>

] 1>没有用户定义的转换
操作符可以执行
此转换，或者操作符
不能调用1> C：\Program
文件（x86）\Microsoft Visual Studio
9.0 \VC\include\xutility（417）：编译类模板成员
function
'std :: _ Container_base_aux_alloc_real< _Alloc> :: _ Container_base_aux_alloc_real（_Alloc）'
1> with 1> [1>

_Alloc = CryptoPP :: AllocatorWithCleanup
1>] 1> C ：\Program Files
（x86）\ Microsoft Visual Studio
9.0 \VC\include\vector（421）：参见类模板
实例化
' std :: _ Container_base_aux_alloc_real< _Alloc>'
正在编译1> with 1>

[1>

_Alloc = CryptoPP :: AllocatorWithCleanup
1>] 1 > C：\Program Files
（x86）\ Microsoft Visual Studio
9.0 \VC\include\vector（439）：参见类模板
实例化
'std :: _ Vector_val< _Ty，_Alloc>'是
编译的1>与1> [1>
_Ty = CryptoPP :: HuffmanDecoder :: CodeInfo，
1>

_Alloc = CryptoPP :: AllocatorWithCleanup
1>] 1>

C：\myproject\sshlib\zinflate.h（79）：
参见类的引用template
instantiation'std :: vector< _Ty，_Ax>'
正在编译1> with 1>

[1>

_Ty = CryptoPP :: HuffmanDecoder :: CodeInfo，
1>

_Ax = CryptoPP :: AllocatorWithCleanup
1>] 1> zinflate.cpp

1>zlib.cpp 1>C:\Program Files (x86)\Microsoft Visual Studio 9.0\VC\include\xutility(419) : error C2664: 'CryptoPP::AllocatorWithCleanup::AllocatorWithCleanup(const CryptoPP::AllocatorWithCleanup &)' : cannot convert parameter 1 from 'CryptoPP::AllocatorWithCleanup' to 'const CryptoPP::AllocatorWithCleanup &' 1> with 1> [ 1>
T=std::_Aux_cont 1> ] 1>
and 1> [ 1>
T=CryptoPP::HuffmanDecoder::CodeInfo 1> ] 1> and 1> [ 1> T=std::_Aux_cont 1>
] 1> Reason: cannot convert from 'CryptoPP::AllocatorWithCleanup' to 'const CryptoPP::AllocatorWithCleanup' 1> with 1> [ 1>
T=CryptoPP::HuffmanDecoder::CodeInfo 1> ] 1> and 1> [ 1> T=std::_Aux_cont 1>
] 1> No user-defined-conversion operator available that can perform this conversion, or the operator cannot be called 1> C:\Program Files (x86)\Microsoft Visual Studio 9.0\VC\include\xutility(417) : while compiling class template member function 'std::_Container_base_aux_alloc_real<_Alloc>::_Container_base_aux_alloc_real(_Alloc)' 1> with 1> [ 1>
_Alloc=CryptoPP::AllocatorWithCleanup 1> ] 1> C:\Program Files (x86)\Microsoft Visual Studio 9.0\VC\include\vector(421) : see reference to class template instantiation 'std::_Container_base_aux_alloc_real<_Alloc>' being compiled 1> with 1>
[ 1>
_Alloc=CryptoPP::AllocatorWithCleanup 1> ] 1> C:\Program Files (x86)\Microsoft Visual Studio 9.0\VC\include\vector(439) : see reference to class template instantiation 'std::_Vector_val<_Ty,_Alloc>' being compiled 1> with 1> [ 1> _Ty=CryptoPP::HuffmanDecoder::CodeInfo, 1>
_Alloc=CryptoPP::AllocatorWithCleanup 1> ] 1>
C:\myproject\sshlib\zinflate.h(79) : see reference to class template instantiation 'std::vector<_Ty,_Ax>' being compiled 1> with 1>
[ 1>
_Ty=CryptoPP::HuffmanDecoder::CodeInfo, 1>
_Ax=CryptoPP::AllocatorWithCleanup 1> ] 1>zinflate.cpp

它最终指向的代码行是：

The line of code it eventually points to is:

std::vector<CodeInfo, AllocatorWithCleanup<CodeInfo> > m_codeToValue;

编辑：更多信息：

当我的预处理器包含NDEBUG而不是_DEBUG时，我得到这个错误。如果我改变我的版本配置为_DEBUG isntead它编译。为什么？

I get this error exactly when my preprocessor contains NDEBUG instead of _DEBUG. If I change my release config to have _DEBUG isntead it compiles. Why?

推荐答案

这是Visual C ++编译器中的一个错误。请参阅 http://old.nabble.com/-jira--Created:-%28QPID-1458%29-C%2B%2B-common-compile-error-in-VC9 -Release-mode-td20469700.html 。

It's a bug in the Visual C++ compiler. See http://old.nabble.com/-jira--Created:-%28QPID-1458%29-C%2B%2B-common-compile-error-in-VC9-Release-mode-td20469700.html.

您可以通过禁用检查迭代器：

#define _SECURE_SCL 0

但请注意：如果您链接到第三方使用 _SECURE_SCL 编译的库，例如提升，内存损坏可能会（并且会发生）。

But be warned: if you link against a third-party library that was compiled with _SECURE_SCL enabled, like e.g. boost, memory corruption can (and will) occur.

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