通过TinyXML深度复制XML [英] Deep Copy an XML via TinyXML

问题描述

我使用tinyxml。

如何复制或创建现有XMLDocument的副本？ b

http://www.grinninglizard.com/tinyxmldocs/classTiXmlDocument .html＃a4e8c1498a76dcde7191c683e1220882

我通过这个链接说过使用克隆复制节点。但是这是受保护的，我不想去推导出这样的类和类似的。

我也不想保存现有的XMLDocument到文件然后让另一个XMLDocument对象读取该文件以具有它的副本。

我也不能使用 memcpy 因为我不知道整个XML的大小。

我也不想让两个对象一个接一个使用，如：

  XMLDocumentObj1 = add_some_data 
 
 XMLDocumentObj2 = add_the_same_data，等等
  

我想要第二个副本的主要原因是，第一个副本可能被代码的不同部分修改，而同一个副本在多个地方被读取 。我需要确保在读取XMLDocument时不会发生错误，因为有可能这可能已经在后台被运行的线程修改，我没有程序崩溃。

解决方案

我发现这一点，我认为这可能会对你有帮助。

https://github.com/leethomason/tinyxml2/blob/master/xmltest。 cpp

  const char * pub =<？xml version ='1.0'？>< element> ;< sub />< / element><！ -  comment  - ><！DOCTYPE>; 
 XMLDocument doc; 
 doc.Parse（pub）; 
 
 XMLDocument clone; 
 for（const XMLNode * node = doc.FirstChild（）; node; node = node-> NextSibling（））{
 XMLNode * copy = node-> ShallowClone（& clone）; 
 clone.InsertEndChild（copy）; 
} 
 
 clone.Print（）; 
 
 int count = 0; 
 const XMLNode * a = clone.FirstChild（）; 
 const XMLNode * b = doc.FirstChild（）; 
 for（; a& b; a = a-> NextSibling（），b = b-> NextSibling（））{
 ++ count; 
 XMLTest（Clone and Equal，true，a-> ShallowEqual（b））; 
} 
 XMLTest（Clone and Equal，4，count）; 
  

I am using tinyxml.

How do I duplicate or create a copy of an existing XMLDocument?

http://www.grinninglizard.com/tinyxmldocs/classTiXmlDocument.html#a4e8c1498a76dcde7191c683e1220882

I went through this link that says using Clone to replicate a node. But this is protected and I do not want to go for deriving a class out of this and the like.

I also do not want to save the existing XMLDocument to a file and then making another XMLDocument object read the file to have a copy of it.

I am also not able to perform a deep copy using memcpy because I am unaware of the size of the entire XML.

I also do not want to having two objects being used one after the other like:

XMLDocumentObj1 = add_some_data

XMLDocumentObj2 = add_the_same_data, and so on

The primary reason I want a second copy is that, the first might be modified by different sections of the code, while the same copy is being 'read' at multiple places. I need to ensure that there occur no errors when XMLDocument is read, because there are chances that this might have been modified in the background by a running thread, and I get no program crashes.

解决方案

I found this and i think this may help you.

https://github.com/leethomason/tinyxml2/blob/master/xmltest.cpp

const char* pub = "<?xml version='1.0'?> <element><sub/></element> <!--comment--> <!DOCTYPE>";
XMLDocument doc;
doc.Parse( pub );

XMLDocument clone;
for( const XMLNode* node=doc.FirstChild(); node; node=node->NextSibling() ) {
    XMLNode* copy = node->ShallowClone( &clone );
    clone.InsertEndChild( copy );
}

clone.Print();

int count=0;
const XMLNode* a=clone.FirstChild();
const XMLNode* b=doc.FirstChild();
for( ; a && b; a=a->NextSibling(), b=b->NextSibling() ) {
    ++count;
    XMLTest( "Clone and Equal", true, a->ShallowEqual( b ));
}
XMLTest( "Clone and Equal", 4, count );

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