如何输出多个（.txt）文件中的内容 [英] How to output content in multiple (.txt) files

问题描述

我创建了一个程序，它可以从一个文件中获取一个整数作为其输入，并生成从1到从该文件读取的整数的乘法表。例如，如果程序从文件读取（3），它将输出：

I created a program that can take an integer as its input from a file and generate multiplication tables from 1 up to that integer read from the file. For example, if the program reads (3) from the file, it will output:

1*1 = 1
1*2 = 2
... up to
1*10 = 10
and then 
2*1 = 1 
.....
2*10 = 10
and so on up to three suppose that the number read from the file is 3
3*1 = 1
....
3*10 = 30

现在，我试图输出不同（.txt）文件中的每个乘法表例如table1.txt将包含 1 * 1 = 1 ....高达1 * 10 = 10 ，table2.txt将包含 2 * 1 = 2 ....最多2 * 10 = 10 和table3.txt中的相同过程。

Now, I am trying to output each multiplication tables in different (.txt) files where for example table1.txt would contain 1*1 = 1 .... up to 1*10 = 10 and table2.txt would contain 2*1 = 2 .... up to 2*10 = 10 and the same procedure for table3.txt.

文件，只包含第一个乘法表，我不知道如何显示其他表在不同的文件。

I can only create one file that only contains the first multiplication table and I do not know how to display the rest of the tables in different files.

我真的很感谢任何帮助或见解解决这个问题。谢谢！

I would really appreciate any help or insights to solve this problem. Thank you!

这是我有的：

#include <iostream>
#include <fstream>

using namespace std;

int main ()
{
    int num, a, b;
    fstream inputStream;
    ofstream outputStream;

    inputStream.open("input.txt"); //let's say input.txt holds the number 3

    while (inputStream >> num)
    outputStream.open("table.txt");

    for (a = 1; a <= num; a++) 
    {
        for (b = 1; b <= 10; b++)
        {
            outputStream << a << " X "
                   << b << " = "
                   << a*b << endl;
        }
        inputStream.close();
        outputStream.close();
    }                  
    return 0;
}

推荐答案

#include <iostream>
#include <string>
#include <fstream>

int main(void) {
    const int Count = 10;              //Count of files
    std::string name = "example_";     //base pattern of file name
    std::ofstream outfstr[Count];      //creating array of 10 output file streams
    for(int i = 0; i < Count; ++i) {   //open all file streams 
        outfstr[i].open(name + char('0' + i) + ".txt");
    }

    for(int i = 0; i < Count; ++i) { // write value of i to i-th stream
         outfstr[i] << "Some rezult " << i;
    }
    return 0;
}

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