在字节数组中嵌入多个int [英] Embed multiple ints in byte array

问题描述

我使用这个代码：

int number; //=smth
unsigned char sendBuffer[255];
sendBuffer[0] = number & 0xFF;
sendBuffer[1] = (number  >> 8) & 0xFF;
sendBuffer[2] = (number  >> 16) & 0xFF;
sendBuffer[3] = (number  >> 24) & 0xFF;

将数字 c $ c> sendBuffer 。

to put number in byte array sendBuffer.

我的问题是：

我想现在嵌入两个数字在字节数组，我应该这样继续？

1) Say I want to embed now two numbers in the byte array, shall I proceed like this?

    sendBuffer[0] = number & 0xFF;
    sendBuffer[1] = (number  >> 8) & 0xFF;
    sendBuffer[2] = (number  >> 16) & 0xFF;
    sendBuffer[3] = (number  >> 24) & 0xFF;
    sendBuffer[4] = number2 & 0xFF;
    sendBuffer[5] = (number2  >> 8) & 0xFF;
    sendBuffer[6] = (number2  >> 16) & 0xFF;
    sendBuffer[7] = (number2  >> 24) & 0xFF;

即使 code> 大小为8或6个字节？
（我这么说是因为在某些平台上int可能是4个字节或6个是正确的
想想如果上面的代码也工作，当数字是6字节吗？
另外要注意的是，即使它是6字节，但我只有
存储4字节整数内部，将上面的代码工作吗？ 。

Will this work even if number is of size say 8 or 6 bytes? (I am saying this because on some platforms the int maybe 4 bytes or 6 right? So I was thinking if the above code also works when number is 6 bytes? Further thing to note is that even if it is 6 bytes, but I only store 4 byte integer inside it, will above code work?).

这个缓冲区通常存储在卡的某些内存上，我没有读取
的问题（例如，endiannes等问题，字节数组，当读取看来是按照我保存的顺序）。

This buffer I usually store on some memory of a card and I don't have problems reading it back (e.g., endiannes etc. issues, the byte array when reading seems to come in the order I saved).

2）最后，如何从字节数组重建整数 sendBuffer ？

2) Finally, how to reconstruct the integer from the byte array sendBuffer?

推荐答案

1）是的，不，它只有4个字节。

1) Yes, proceed like that. No, it only works for 4 bytes.

有一个更简单，更好的方法来做到这一点，虽然如果缓冲区从一台计算机发送，它可能会导致字节顺序问题另一个使用不同的架构。假设你知道 number 的类型，在 sendBuffer 之上覆盖另一个数组。

There is a easier, better way to do this, although it can cause endianness issues if the buffer is sent from one computer to another which uses a different architecture. Assuming you know the type of number, overlay another array on top of sendBuffer.

unsigned char sendBuffer[255];
number_type *sendBufferNum = (number_type*) sendBuffer;
sendBufferNum[0] = number;
sendBufferNum[1] = number2;

以同样的方式读取数字。

Reading a number can be done the same way.

unsigned char receiveBuffer[255];
//read values into receiveBuffer
number_type *receiverBufferNum = (number_type*) receiveBuffer;
number_type number = recieveBuffer[0];
number_type number2 = receiveBuffer[1];

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