将类型转换为无符号短整型 [英] type cast char to Unsigned short

问题描述

我试图将字符转换为无符号短，但我得到的值m_cmdCode总是0.一些输入将是非常有帮助的。

I'm trying to convert the characters to unsigned short but the value I'm getting in m_cmdCode is always 0. Some input would be very helpful.

int main()
{
 char *temp = new char[3];
 memset(temp,1,3);
 unsigned short m_cmdCode = (unsigned short) atoi(temp);
 printf("%d",m_cmdCode);
}

//我想让m_cmdCode等于111，

// I want m_cmdCode to be equal to 111, is it possible to do this ?

推荐答案

您正在将 temp 的元素设置为整数值 1 。你想要的字符值'1'：

You're setting the elements of temp to the integer value 1. You want the character value '1':

memset(temp, '1', 3);

注意，你还需要NUL终止 temp atoi 可靠地工作。

Note that you also need to NUL-terminate temp for atoi to work reliably.

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