带指针的ostream_iterator [英] ostream_iterator with pointers

问题描述

让

Foo.hpp：

class Foo
{
    public:
    void print() const;
    protected:
    vector<Bar<string, int>*> bar_;
};

void Foo::print() const
{
    copy(bar_.begin(), bar_.end(), ostream_iterator<Bar<string, int>*>(cout, "\n"));
}

Bar.hpp：

class Bar
{
    public:
    template <typename K, typename U>
    friend ostream& operator<<(ostream&, const Bar<K, U>&);
}

template <typename Key, typename T>
ostream& operator<<(ostream& out, const Bar<Key, T>& bar)
{
    return out << "FOOBAR";
}

其中bar_是Foo的属性， 。假设bar_有一个元素，然后输出：

Where bar_ is an attribute of Foo and is a vector of pointers to Bar elements. Assume bar_ has one element, then the output of :

Foo foo;
foo.print();

是bar_中元素的地址，而不是FOOBAR。如果我不使用指针，输出将是FOOBAR我想要实现这里是打印FOOBAR的每个指针的bar _。

is the address of the element in bar_, instead of "FOOBAR". If I wouldn't use pointers, the output would be "FOOBAR" What I'm trying to achieve here is to print "FOOBAR" for each pointer of bar_.

推荐答案

尝试添加：

template <typename Key, typename T>
ostream& operator<<(ostream& out, Bar<Key, T>* bar)
{
    return out << *bar;
}

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