如何使用Rand（）随机选择变量 [英] How To Randomly Pick A Variable Using Rand()

问题描述

我想用C ++编写一个基于文本的战斗机，这是我做的第一件事之一。到目前为止我有这个：

I am trying to make a text based fighter in C++, this is one of the first things that I have done. So far I have this:

//Text Based Fighter

#include <iostream>
#include <stdlib.h> //srand, rand
#include <string>

using namespace std;

int main() {

    //Player
    int playerHealth = 100;
    int attack1;
    int attack2;
    int attack3;
    string attack;
    int npc1;
    int npc2;

    cout << "Do you want to attack " << rand()[npc1,npc2];

    //varname = rand() % 10 + 1;

return 0;
}

我想要做的是在npc1和npc2之间随机选择，谢谢您。

What I am wanting it to do is randomly pick between npc1 and npc2, thank you.

还有关于我如何写我的代码的任何意见将不胜感激，我只是开始几天前谢谢你，如果你需要任何更多的细节，请随意

Also any comments on how I am writing my code would be appreciated, I have only started a couple of days ago thank you, if you need any more detail please feel free to ask, thank you.

推荐答案

对于只有2个选项，您可以使用三元表达式从2取余数：

For just 2 choices you can take the remainder from 2 with a ternary expression:

int choice = rand() % 2 == 0 ? npc1 : npc2;

如果你有两个以上的选择，即使你没有，你可以做一个数组

If you have more than 2 choices, or even if you don't, you can make an array with those and index into it.

int npc_choices[2];
int choice = npc_choices[rand() % 2];

如果选择的数量不是2的幂，你很可能会在用％运算符进行选择。如果你不是任何具有统计意义或有大量选择的东西，我不会担心。

If the number of choices is not a power of 2 you will likely introduce a very small bias into the selection with the modulo % operator. If you're not working on anything with statistical significance or with a huge number of choices I wouldn't worry about it.

这篇关于如何使用Rand（）随机选择变量的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！