goto语句的另一种方法在C ++ [英] Alternative way for goto statement in C++

问题描述

以下是流程图的链接：
http://i1146.photobucket.com/albums/o530/HTHVampire/C%20plus%20plus/Capture_zps5a6c3acf.jpg

这是流程图的代码，如图所示，只是忽略流程图中的模糊语句。

  #include< iostream> 
 using namespace std; 
 
 int main（）
 {
 //声明并初始化变量
 int a = 0; 
 //提示用户输入值
 cout<< 请输入值< endl; 
 cin>>一个; 
 
 again1：
 //输入决策块
 if（a> 10）
 {
 if（a <10）
 {
 again2：
 if（a< 100）
 {
a = a  -  3; 
 goto again2; 
} 
 else goto again1; 
} 
 else 
 {
 a = a  -  7; 
 goto again1; 
} 
} 
 else cout<< 输出是< a<< endl; 
 
 return 0; 
} 
  

我可以知道我可以用if-else语句while语句？

解决方案

<该结构应当根据流程图执行核心逻辑：

  while（a> 10）{
 if a< 10）{
 while（a <100）{
a + = 3; 
} 
} else {
 a  -  = 7; 
} 
} 
  

注意 if test是荒谬的。但是，我没有画出流程图;我刚刚在代码中复制。

Here's the link for the flowchart: http://i1146.photobucket.com/albums/o530/HTHVampire/C%20plus%20plus/Capture_zps5a6c3acf.jpg

Here's the code for the flowchart as shown, just ignore the ambiguous statement in the flowchart.

#include <iostream>
using namespace std;

int main()
{
    //declare and initialize a variable
    int a = 0;
    //prompt user for a value
    cout << "please enter a value" << endl;
    cin >> a;

    again1:
    //enter a decision block
    if(a > 10)
    {
        if(a < 10)
        {
            again2:
            if(a < 100)
            {
                a = a - 3;
                goto again2;
            }
            else goto again1;
        }
        else
        {
            a = a - 7;
            goto again1;
        }
    }
    else cout << "the output is " << a << endl;

    return 0;
}

May I know that can I play this code with if-else statement together with while statement? instead of goto statement.

Thanks for your guides!

解决方案

This structure should do the core logic according to the flowchart:

while (a > 10) {
    if (a < 10) {
        while (a < 100) {
            a += 3;
        }
    } else {
        a -= 7;
    }
}

Note that the if test is absurd. However, I didn't draw the flowchart; I just reproduced it in code.

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