如何将xml文件的节点存储在字符串数组中，然后存储到C ++中的结构 [英] How to store the node of an xml file in a string array and then to a structure in C++

问题描述

我有一个类似如下的xml文件： -

Disp.xml：

 < Car> 
< Car1> 
< Feature1> 50< / Feature1> 
< Feature2> 100< / Feature2> 
< Feature3> 10< / Feature3> 
< / Car1> 
< Car2> 
< Feature1> 100< / Feature1> 
< Feature2> 100< / Feature2> 
< Feature3> 10< / Feature3> 
< / Car2> 
< Car3> 
< Feature1> 500< / Feature1> 
< Feature2> 0< / Feature2> 
< Feature3> 10< / Feature3> 
< / Car3> 
< Car4> 
< Feature1> 1000< / Feature1> 
< Feature2> 0< / Feature2> 
< Feature3> 0< / Feature3> 
< / Car4> 
< / Car> 
  

Xml阅读代码：

  XmlDocument ^ xDoc = gcnew XmlDocument（）; 
 String ^ XPath = ---文件路径
 xDoc-> Load（XPath）; 
 XmlNodeList ^ nodes1 = xDoc-> GetElementsByTagName（Car）; 
 XmlNodeList ^ car1 = xDoc-> GetElementsByTagName（Car1）; 
 XmlNodeList ^ car1 = xDoc-> GetElementsByTagName（Car2）; 
每个（节点1中的XmlNode ^ node1）
 {
每个（XmlNode ^ car1中的ca1）
 {
 feature1 = ca1-> ChildNodes [1] - > ChildNodes [0]  - > Value-> ToString（）; 
 feature2 = ca1-> ChildNodes [2]  - > ChildNodes [0]  - > Value-> ToString（）; 
 feature3 = ca1-> ChildNodes [3]  - > ChildNodes [0]  - > Value-> ToString（）; 
} 
} 
  

我有一个结构

示例： -

  struct Car1 
 { 
 std :: string feature1; 
 std :: string feature2; 
 std :: string feature3; 
} 
  

同样，我也有其他结构。

我需要读取每个汽车的节点（值）并将其存储在Car1，Car2，Car3，Car4字符串数组中，这些字符串值必须稍后存储在C ++的单个结构中。

我必须在C ++类库中做所有这些。

很多研究确实让我找到只读的xml数据但不是存储在字符串数组和以后的个人结构和C ++中。

解决方案

我最喜欢的在C ++中阅读XML的工具 http://pugixml.org/

只需使用（或另一个）库读取值，然后将它们保存到struct

I have an xml file that looks like this :-

Disp.xml:

<Car>
<Car1>
    <Feature1>50</Feature1>
    <Feature2>100</Feature2>
    <Feature3>10</Feature3>
</Car1>
<Car2>
    <Feature1>100</Feature1>
    <Feature2>100</Feature2>
    <Feature3>10</Feature3>
</Car2>
<Car3>
    <Feature1>500</Feature1>
    <Feature2>0</Feature2>
    <Feature3>10</Feature3>
</Car3>
<Car4>
    <Feature1>1000</Feature1>
    <Feature2>0</Feature2>
    <Feature3>0</Feature3>
</Car4>
</Car>

Code for Xml reading :-

XmlDocument^ xDoc = gcnew XmlDocument();
String^ XPath =  ---path of file
xDoc->Load(XPath);
XmlNodeList^ nodes1 = xDoc->GetElementsByTagName("Car");
XmlNodeList^ car1 = xDoc->GetElementsByTagName("Car1");
XmlNodeList^ car1 = xDoc->GetElementsByTagName("Car2");
 for each (XmlNode^ node1 in nodes1)
 {          
    for each(XmlNode^ca1 in car1)
    {
        feature1= ca1->ChildNodes[1]->ChildNodes[0]->Value->ToString(); 
        feature2= ca1->ChildNodes[2]->ChildNodes[0]->Value->ToString(); 
        feature3= ca1->ChildNodes[3]->ChildNodes[0]->Value->ToString(); 
    }
}

I do have a structure

Example :-

struct Car1  
{
std::string feature1;
std::string feature2;
std::string feature3;
}

Similarly I have other structure too.

I need to read the nodes(values) of each car and store it in Car1,Car2,Car3,Car4 string array ,these string values must be later stored in individual structure in C++.

I have to do all this within a C++ Class Library .

A lot of research did let me find out only read xml data but not to store in string array and later in individual structure and that too in C++.

解决方案

My favourite tool for reading XML in C++ http://pugixml.org/

Just read the values using that (or another) library and then save them to your struct

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