没有构造函数的实例“AcademicStaff :: AcademicStaff”匹配参数列表 [英] no instance of constructor "AcademicStaff::AcademicStaff" matches the argument list

问题描述

我宣布了

AcademicStaff(int, char *, char *, int , char *, char *,int, char *,char *) 

initiliazing的构造函数。

constructor for initiliazing.

当我主要调用函数时出现错误

When I called the functiion in main I got an error

 "  2   IntelliSense: no instance of constructor "AcademicStaff::AcademicStaff" matches the argument list
            argument types are: (int, char, char, int, char, char, int, char, char)".

调用函数：

AcademicStaff headOdDepartment(staffID, *firstName, *lastName, telNo, *address, *email, annualSalary, *title, *status);
myDepartment.setheadOfDepartment(headOdDepartment);

推荐答案

您需要调用 AcademicStaff headOdDepartment（staffID，firstName，lastName，telNo，address，email，annualSalary，title，status）;
如果您发送 * charArray 。

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