cin.get（）和省略换行符 [英] cin.get() and omitting newline char

问题描述

我有一个小，简单的程序与菜单和子菜单。用户从1-9中选择并点击进入。我想代码读取只有数字1-9删除\\\
从stdin。我已经尝试sth这样：

I have a small, simple program with menu and submenus. User choose from 1-9 and hits enter. I want the code to read ONLY numbers 1-9 removing "\n" from stdin. I've tried sth like this:

#include <cstdio>
#include <iostream>

using std::cin;
using std::cout;
using std::endl;

class cProgram
{
  private:
    char W;

  public:
    char choice(void);
    void choice(int _W);

    void showSubeMenu1(void);
    void showSubeMenu2(void);
    void showMainMenu(void);
};

char cProgram::choice()
{  return W;  };

void cProgram::choice(int _W)
{  W = _W;  };

void cProgram::showMainMenu(void)
{
  cout << "MAIN MENU:" << endl
       << "[1] option 1" << endl
       << "[2] option 2" << endl
       << "<0> quit" << endl
       << "Your choice: ";
  choice(cin.get());
  getchar();
}

switch (choice())
{
  case '1': choice('n'); showSubeMenu1(); break;    
  case '2': choice('n'); showSubeMenu2(); break;
  case '0': break; // EXITS the program
  default: choice('n'); showMainMenu(); break;
}  

// choice('n'); sets W to neutral char (not 1,2 or 0)

一切正常，直到用户命中\\\
而不是普通键。 正常我的意思不是\\\
。所以，当用户点击enter，它是一个必须再次输入（连续两次）。

Everything works fine, until the user hits "\n" instead of normal key. By "normal" i mean not "\n". So, when the user hits enter, it is a must to hit enter again (twice in a row). Other way the program behaves weird.

推荐答案

我不知道你的问题，但我有几个技巧。当你使用C ++时，你应该使用 std :: cout 和 std :: cin 来输入和输出。它们是从库< iostream> 的流。你也可以使用命名空间std; 编写，然后你不需要写 std :: 。函数 printf（）来自C，并且类型不安全，因此您不应在C ++中使用它。

I am not sure about your problem but I have a few tips for you. When you are using C++ then you should use std::cout and std::cin for input and output. They are stream from library <iostream>. You can also write using namespace std; and then you needn't write std::. Function printf() comes from C and is type unsafe so you shouldn't use it in C++.

流提供许多功能，用于获取有关成功或不成功的阅读/写入等信息。我真的很推荐给你。

Also streams offer many functions for getting information about successful or unsuccessful reading/writing etc. I really recommend it to you.

方法 cin.get 只读取1个字符，也可以是白色字符（'\\\
'，'\t'，''）。如果你想读取数字并忽略空格（默认情况下它们像分隔符），那么你可以使用这个代码：

Method cin.get() reads only 1 character and it also can be a white character ( '\n', '\t', ' ' ). If you would like read number and ignore white spaces ( in default they are used like separators ) then you can use this code:

int x;
cin >> x;
if ( cin.fail() ) cout << "Reading error. It is not a number." << endl;
// cin.eof() means end of file, in this case it is end of input stream

$ b b

我知道当你想要读取东西，然后用户必须写入请求的数据和'\\\
'。字符\\\
很重要。我从来没有尝试过，但我认为它可以重新定义。我在某处阅读。

I know when you want read something then user have to write requested data and '\n'. Character '\n' is important. I have never tried it but I think that it can be redefined. I read it somewhere.

我希望我的提示有用

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