将当前日期保存到3 Ints - C ++ [英] Save Current Date into 3 Ints - C++

问题描述

我想将当前日，月和年保存为三个int。我不知道该怎么做。

I would like to save the current day, month, and year into three ints. I have no idea how to do this.

int day;
int month;
int year;

推荐答案

#include <ctime>

int main() {
    time_t t = time(0);  // current time: http://cplusplus.com/reference/clibrary/ctime/time/
    struct tm * now = localtime(&t);  // http://cplusplus.com/reference/clibrary/ctime/localtime/

    // struct tm: http://cplusplus.com/reference/clibrary/ctime/tm/
    int day = now->tm_mday;
    int month = now->tm_mon + 1;
    int year = now->tm_year + 1900;
}

上面的链接

• time（0）：当前时间：
  http://cplusplus.com/reference/clibrary/ctime/time/


• localtime ：
  http://cplusplus.com/reference/clibrary/ctime/localtime/


• struct tm ：
  http：//cplusplus.com/reference/clibrary/ctime/tm/



Links from above

• time(0): current time: http://cplusplus.com/reference/clibrary/ctime/time/
• localtime: http://cplusplus.com/reference/clibrary/ctime/localtime/
• struct tm: http://cplusplus.com/reference/clibrary/ctime/tm/

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