是否可以在单行中初始化具有增加值的向量？ [英] Is it possible to initialize a vector with increasing values in a single line?

问题描述

有可能在初始化列表或其他C ++功能的帮助下将两个初始化行合并成一个语句吗？向量值总是递增1，但大小 n 不固定。

Is it possible to merge the two initialization lines into a single statement with the help of initializer lists or other C++ features? The vector values always increment with one, but the size n is not fixed.

#include <numeric>
#include <vector>
#include <iostream>

int main()
{
    int n = 10;

    // Can the two lines below be combined into a single statement?
    std::vector<int> v(n);
    std::iota(v.begin(), v.end(), 1);

    for (int i : v)
        std::cout << i << std::endl;

    return 0;
}

推荐答案

=http://www.boost.org/doc/libs/release/libs/iterator/doc/counting_iterator.html> Boost.counting_iterator ：

You can use Boost.counting_iterator for this:

std::vector<int> v(boost::counting_iterator<int>(1),
                    boost::counting_iterator<int>(n + 1));

（ Live ）现在这是否值得，并且比你已经有的更容易阅读，这是你决定。

(Live) Now whether this is worth it and easier to read than what you already have is for you to decide.

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