constexpr（gcc）错误：在'{'token之前不允许包含括号的初始化程序 [英] Error with constexpr(gcc) - error: a brace-enclosed initializer is not allowed here before '{' token

问题描述

struct X {
constexpr static char a1[] = "hello"; // Okay
constexpr static const char* a2[] = {"hello"}; // Error
};

int main(){}

使用gcc编译时出现错误：

Compiling with gcc gives the error:

错误：在'{'token

error: a brace-enclosed initializer is not allowed here before '{' token

这是非法使用constexpr吗？

Is this an illegal use of constexpr?

EDIT

我试过3个不同版本的gcc，它编译在最新的4.7.0我有（我只是下载它，我使用mingw-w64），所以它看起来是一个修复的bug

I tried 3 different versions of gcc, and it compiled on the newest 4.7.0 I have (I just downloaded it, I'm using mingw-w64), so it looks to be a fixed bug (a link to the bug would be nice though!).

4.7.0 20120311（prerelease）//好了

4.6.4 20120305（prerelease）//错误

4.7.0 20110829（实验性）//错误

4.7.0 20120311 (prerelease) // Okay
4.6.4 20120305 (prerelease) // Error
4.7.0 20110829 (experimental) // Error

推荐答案

这是一个已修复的错误。我已经确认代码编译与 g ++ 4.7.0 20120311（prerelease）。

This is a bug which has been fixed. I have confirmed that the code compiles with g++ 4.7.0 20120311 (prerelease).

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