std :: bind和boost :: bind与多态性之间的区别 [英] Difference between std::bind and boost::bind with polymorphism

问题描述

我有一个派生类，我绑定一个虚拟函数，我没有在这个类重写，所以我希望调用父类之一。

使用boost（1.55）很好，但如果我从C ++ 11切换到std :: bind，它拒绝编译

I have a derived class from which I bind a virtual function that I did not override in this class, so I'm hoping to call the one of the parent class.
It works nice with boost (1.55), but if I switch to std::bind from C++11, it refuse to compile with

错误C2100：非法间接
1>功能（1152）：参见函数模板实例化_Rx std :: _ Pmf_wrap< _Pmf_t，_Rx，_Farg0，_V0_t，_V1_t，_V2_t，_V3_t ，_V4_t，_V5_t，> :: operator（）（_ Wrapper&）const'
1>与
1> [
1> _Rx = bool，
1> _Pmf_t = bool（__thiscall Base :: *）（void），
1> _Farg0 = Base，
1> _V0_t = std :: _ Nil，
1> _V1_t = std :: _
1> _V2_t = std :: _ Nil，
1> _V3_t = std :: _Nil，
1> _V4_t = std :: _Nil，
1> _V5_t = std :: _Nil，
1> = std :: _ Nil，
1> _Wrapper = Derived
1>]

error C2100: illegal indirection 1> functional(1152) : see reference to function template instantiation '_Rx std::_Pmf_wrap<_Pmf_t,_Rx,_Farg0,_V0_t,_V1_t,_V2_t,_V3_t,_V4_t,_V5_t,>::operator ()(_Wrapper &) const' being compiled 1> with 1> [ 1> _Rx=bool, 1> _Pmf_t=bool (__thiscall Base::* )(void), 1> _Farg0=Base, 1> _V0_t=std::_Nil, 1> _V1_t=std::_Nil, 1> _V2_t=std::_Nil, 1> _V3_t=std::_Nil, 1> _V4_t=std::_Nil, 1> _V5_t=std::_Nil, 1> =std::_Nil, 1> _Wrapper=Derived 1> ]

这是一个最小代码

class Runnable { virtual bool Run() =0;};
class Base : public Runnable { bool Run() {/*do stuff*/ return true;}};
class Derived : public Base {};

Derived d;
std::function<bool()> f = std::bind(&Derived::Run,std::ref(d)); //Do not compile
std::function<bool()> f = boost::bind(&Derived::Run,boost::ref(d)); //compile 

这不是一个大问题，因为我可以坚持boost，

It's not a major issue, since I can stick with boost, but I would really want to know what's the difference between the two.

我已经在这里检查了几个问题，但我不认为它将如何与这。
Checked stroustrup的网站太这里，但我没有看看任何可以解释这个行为的东西。

我在这里缺少什么？

I've checked few questions in here but I don't think how it will be related to this. Checked stroustrup's site too here, but I did not see anything that could explain this behaviour.
What am I missing here ?

Ps：我使用VS2012 Update 4，如果这可以帮助

Ps: I work with VS2012 Update 4, if this can help

推荐答案

Visual Studio 2012有很多与 std :: function 和 std :: bind 。这是其中之一;该代码将在Visual Studio 2010和Visual Studio 2013中工作。

Visual Studio 2012 has a lot of bugs relating to std::function and std::bind. This is one of them; the code will work in both Visual Studio 2010 and Visual Studio 2013.

最好的选择是只使用Boost.Function和Boost.Bind。

The best choice is to use Boost.Function and Boost.Bind exclusively.

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