完全模仿nullptr [英] Perfectly emulate nullptr

问题描述

我厌倦了等待编译器支持 nullptr （

I got tired of waiting for compiler support of nullptr (gcc 4.6 does but it's so new few distributions support it).

因此，作为一个停止间隙，直到 nullptr 是完全支持我决定模仿它。有两个仿真示例：一个来自此处，一个来自 wikibooks 。

So as a stop gap until nullptr is fully supported I decided to emulate it. There are two examples of emulation: one from here, and one from wikibooks.

值得注意的是，两个实现都没有提到 operator == 。但是，如果没有其他代码，将无法编译。

Of note, neither implementation mentions an operator ==. However, without one, the following code will not compile.

int* ptr = nullptr;
assert( ptr == nullptr ); // error here: missing operator ==

这是 / code>错误编译器错误？

是运算符== （和！= nullptr的， ，，<= ？

模拟的 nullptr 与真实交易之间还有什么不同？

Is this operator == error a compiler bug?
Is operator == (and !=, <, <=, etc) needed to more perfectly emulate nullptr?
What else is different between an emulated nullptr and the real deal?

推荐答案

您使用C ++ 0x编译器编译失败的未知原因。它在C ++ 03中编译良好。

You compiled it with C++0x compiler that failed for unknown reason. It compiles fine in C++03.

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