获得2次的持续时间 [英] Geting duration of 2 times

问题描述

如何获取两个字符串的持续时间，格式为 YYYYMMDDTHHMMSS ？

使用Calendar类并检查 getTimeInMillis（）。问题我有这个是，它是不一致的。任何想法我做错了什么？
每次我运行这个程序，我得到40-70行输出到控制台，当它应该是无。

  public class DurationTester {
 
 / ** 
 *获取两个给定时间之间的持续时间
 * @param time1 yyyymmddThhmmss 
 * @param time2 yyyymmddThhmmss 
 * @ return time1和time2之间的分钟
 * / 
 public static int getDuration（String time1，String time2）{
 int yyyy1 = Integer.parseInt（time1.substring（0,4））; 
 int mm1 = Integer.parseInt（time1.substring（4,6））; 
 int dd1 = Integer.parseInt（time1.substring（6,8））; 
 int hh1 = Integer.parseInt（time1.substring（9,11））; 
 int min1 = Integer.parseInt（time1.substring（11,13））; 
 
 int yyyy2 = Integer.parseInt（time2.substring（0,4））; 
 int mm2 = Integer.parseInt（time2.substring（4,6））; 
 int dd2 = Integer.parseInt（time2.substring（6,8））; 
 int hh2 = Integer.parseInt（time2.substring（9,11））; 
 int min2 = Integer.parseInt（time2.substring（11,13））; 
 
日历cal1 = Calendar.getInstance（）; 
 cal1.set（yyyy1，mm1，dd1，hh1，min1，0）; 
日历cal2 = Calendar.getInstance（）; 
 cal2.set（yyyy2，mm2，dd2，hh2，min2，0）; 
 long milliSec = cal1.getTimeInMillis（） -  cal2.getTimeInMillis（）; 
 long nonNegativeMS = Math.abs（milliSec）; 
 long seconds = nonNegativeMS / 1000; 
 long minutes = seconds / 60; 
 return（int）minutes; 
} 
 
 public static void main（String [] args）{
 String t1 =20130108T150000; 
 String t2 =20130108T131500; 
 
 int errors = 0; 
 for（int i = 0; i <5000; i ++）{
 int duration = getDuration（t1，t2）; 
 if（duration == 104）{
 System.out.println（ERROR：Should only be 105（+ errors ++ +））; 
} 
} 
} 
} 
  

解决方案

这是一个记录的错误。 / p>

请尝试在设置之前清除日历：

  cal1.clear ; 
 cal1.set（yyyy1，mm1，dd1，hh1，min1，0）; 
 
 cal2.clear（）; 
 cal2.set（yyyy2，mm2，dd2，hh2，min2，0）; 
  

How can I get the duration of two Strings in the format YYYYMMDDTHHMMSS?

I´m trying with using the Calendar class and checking the getTimeInMillis(). Problem I am having with this is that it is not consistent. Any idea what I am doing wrong? Every time I run this program I get 40-70 lines of output to console when it should be none.

public class DurationTester {

    /**
     * Get the duration between two given times
     * @param time1 yyyymmddThhmmss
     * @param time2 yyyymmddThhmmss
     * @return minutes between time1 and time2
     */
    public static int getDuration(String time1, String time2){
        int yyyy1 = Integer.parseInt(time1.substring(0,4));
        int mm1 = Integer.parseInt(time1.substring(4,6));
        int dd1 = Integer.parseInt(time1.substring(6,8));
        int hh1 = Integer.parseInt(time1.substring(9,11));
        int min1 = Integer.parseInt(time1.substring(11,13));

        int yyyy2 = Integer.parseInt(time2.substring(0,4));
        int mm2 = Integer.parseInt(time2.substring(4,6));
        int dd2 = Integer.parseInt(time2.substring(6,8));
        int hh2 = Integer.parseInt(time2.substring(9,11));
        int min2 = Integer.parseInt(time2.substring(11,13));

        Calendar cal1 = Calendar.getInstance();
        cal1.set(yyyy1, mm1, dd1, hh1, min1, 0);
        Calendar cal2 = Calendar.getInstance();
        cal2.set(yyyy2, mm2, dd2, hh2, min2, 0);
        long milliSec = cal1.getTimeInMillis()-cal2.getTimeInMillis();
        long nonNegativeMS = Math.abs(milliSec);
        long seconds = nonNegativeMS / 1000;
        long minutes = seconds / 60;        
        return (int)minutes;
    }

    public static void main(String[] args){
        String t1 = "20130108T150000";
        String t2 = "20130108T131500";

        int errors = 0;
        for(int i=0; i<5000; i++){
            int duration = getDuration(t1,t2);
            if(duration == 104){
                System.out.println("ERROR: Should only be 105 ("+errors++ +")");
            }
        }
    }
}

解决方案

That's a documented bug.

Try clearing the calendar before set:

cal1.clear();
cal1.set(yyyy1, mm1, dd1, hh1, min1, 0);

cal2.clear();
cal2.set(yyyy2, mm2, dd2, hh2, min2, 0);

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