Groovy：获得多年的持续时间 [英] Groovy: Get duration in years

问题描述

在groovy中运行以下代码 -

  import groovy.time。* 
 import org.codehaus。 groovy.runtime.TimeCategory 
 def today = new Date（）
 use（TimeCategory）
 {
 def modifiedToday = today.plus（10.minutes）
 modifiedToday = modifiedToday.plus（10.months）
 modifiedToday = modifiedToday.plus（10.years）
 def duration = modifiedToday  -  today 
 println duration.years 
 println duration.months 
 println duration.days 
 println duration.minutes 
} 
  

我是获得以下输出 -

  0 
 0 
 3956 
 10 
  

请建议，为什么我会将年和月数作为0和所有的天数值。

解决方案

如何在几个月内得到这个价值？

每个月有不同的天数，那么你会做什么？

你可以从现在开始，做：

  println duration.from.now 
  

或者，您可以通过以下方式获取过去代表的日期：

  println duration.ago 
  

我想你可以从那里工作，基于给定日期对TimeDuration进行归一化的内置功能

---

编辑

这种事情从过去的一个日期滚动到指定的日期。我还没有做任何真正的测试，所以你应该在使用它的任何重要的...之前应该关心和测试生活。

  import static java.util.Calendar。* 
 import groovy.time.DatumDependentDuration 
 import groovy.time.TimeCategory 
 
 DatumDependentDuration getAge（Date dob， Date now = new Date（））{
 dob.clearTime（）
 now.clearTime（）
 assert dob<现在
 Calendar.instance.with {c  - > 
 c.time = dob 
 def（years，months，days）= [0，0，0] 
 
 while（（c [YEAR]< now [YEAR] -  1）|| 
（c [YEAR]< now [YEAR]&& c [MONTH]< = now [MONTH]））{
 c.add（YEAR，1） 
年++ 
} 
 
 while（（c [YEAR]< now [YEAR]）|| 
（c [MONTH]< now [MONTH] ;& c [DAY_OF_MONTH]< = now [DAY_OF_MONTH]））{
 //当我们正在包装DEC / JAN边框时收到，并且会超过现在
 if（c [YEAR] = =现在[YEAR]  -  1& 
现在[MONTH] == JANUARY&& c [MONTH] == DECEMBER&& 
c [DAY_OF_MONTH]> now [DAY_OF_MONTH] ）{
 break 
} 
 c.add（MONTH，1）
 months ++ 
} 
 
 while（c [DAY_OF_YEAR]！=现在[DAY_OF_YEAR]）{
 c.add（DAY_OF_YEAR，1）
 days ++ 
} 
 
 new DatumDependentDuration（y耳朵，月，日，0，0，0，0）
} 
} 
 
 println getAge（Date.parse（'dd / MM / yyyy'，' 10/2000'））
 
 //打印：'12年，2个月，30天'
  

On running the following code in groovy -

import groovy.time.*
import org.codehaus.groovy.runtime.TimeCategory
def today = new Date()
use(TimeCategory)
{
  def modifiedToday = today.plus(10.minutes)
  modifiedToday = modifiedToday.plus(10.months)
  modifiedToday = modifiedToday.plus(10.years)
  def duration = modifiedToday - today
  println duration.years
  println duration.months
  println duration.days
  println duration.minutes
}

I am getting the following output -

0
0
3956
10

Please suggest, why am I getting years and months as 0 and all the value in days. How do I get the value in years and months?

解决方案

How would you get it in months?

Each month has a different number of days, so what would you do?

You can get back the date this represents from now by doing:

println duration.from.now

Or, you can get the date that represents in the past by doing:

println duration.ago

And I guess you could work it out from there, but there is no in-built functionality for normalising a TimeDuration based on a given date

---

Edit

This sort of thing rolls from one date in the past to the specified date. I haven't done any real testing on it though, so you should take care and test the life out of it before using it in anything important...

import static java.util.Calendar.*
import groovy.time.DatumDependentDuration
import groovy.time.TimeCategory

DatumDependentDuration getAge( Date dob, Date now = new Date() ) {
  dob.clearTime()
  now.clearTime()
  assert dob < now
  Calendar.instance.with { c ->
    c.time = dob
    def (years, months, days) = [ 0, 0, 0 ]

    while( ( c[ YEAR ] < now[ YEAR ] - 1 ) || 
           ( c[ YEAR ] < now[ YEAR ] && c[ MONTH ] <= now[ MONTH ] ) ) {
      c.add( YEAR, 1 )
      years++
    }

    while( ( c[ YEAR ] < now[ YEAR ] ) ||
           ( c[ MONTH ] < now[ MONTH ] && c[ DAY_OF_MONTH ] <= now[ DAY_OF_MONTH ] ) ) {
      // Catch when we are wrapping the DEC/JAN border and would end up beyond now
      if( c[ YEAR ] == now[ YEAR ] - 1 &&
          now[ MONTH ] == JANUARY && c[ MONTH ] == DECEMBER &&
          c[ DAY_OF_MONTH ] > now[ DAY_OF_MONTH ] ) {
        break
      }
      c.add( MONTH, 1 )
      months++
    }

    while( c[ DAY_OF_YEAR ] != now[ DAY_OF_YEAR ] ) {
      c.add( DAY_OF_YEAR, 1 )
      days++
    }

    new DatumDependentDuration( years, months, days, 0, 0, 0, 0 )
  }
}

println getAge( Date.parse( 'dd/MM/yyyy', '11/10/2000' ) )

// Prints: '12 years, 2 months, 30 days'

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