算法进程回调 [英] Algorithm progress callback

问题描述

我必须实现非常复杂的算法与许多迭代，矩阵运算等。有两个主要循环的傅立叶级数近似。我想知道什么是实现进度回调的最佳方法。我不久的将来我想在WPF应用程序中使用这种算法，我想实现进度栏。

I have to implement very complex algorithm with a lot of iterations, matrix operations etc. There are two major loops for Fourier series approximation. I would like to know what is the best approach to implement progress callback. I na future I would like to use this algorithm in WPF app and I would like to implement progress bar. How to prepare algorithm to make progress bar implementaion easy in a future?

我正在考虑这样的东西：

I am thinking about something like this:

static void Main(string[] args)
{
    Console.Write("Progres...  ");
    Alg((i) => UpdateProgress(i));            
}

public static void UpdateProgress(int iteration)
{
    string anim = @"|/-\-";            
    Console.SetCursorPosition(Console.CursorLeft - 1, Console.CursorTop);
    Console.Write(anim[iteration%5]);                        
}

public static void Alg(Action<int> progressCallback)
{
    for (int i = 0; i < 100; i++)
    {
        Thread.Sleep(50);
        progressCallback(i);
    }
}

推荐答案

你更喜欢使用 TPL ，为什么不坚持呢？
您可以使用IProgress http://msdn.microsoft.com /pl-pl/library/hh193692.aspx 。

If you prefer to use TPL, why not stick with it? You can use 'IProgress' http://msdn.microsoft.com/pl-pl/library/hh193692.aspx .

class Program
{
    static void Main(string[] args)
    {
        Console.Write("Progres...  ");

        Progress<int> progress = new Progress<int>();

        var task = Alg(progress);            

        progress.ProgressChanged += (s, i) => { UpdateProgress(i); };

        task.Start();
        task.Wait();
    }

    public static void UpdateProgress(int iteration)
    {
        string anim = @"|/-\-";
        Console.SetCursorPosition(Console.CursorLeft - 1, Console.CursorTop);
        Console.Write(anim[iteration % anim.Count()]);
    }

    public static Task Alg(IProgress<int> progress)
    {
        Task t = new Task
        (
            () =>
            {
                for (int i = 0; i < 100; i++)
                {
                    Thread.Sleep(50);
                    ((IProgress<int>)progress).Report(i);
                }
            }
        );
        return t;
    }
}

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