是否有一个正则表达式的味道，让我来算匹配的*和+运营商重复的次数？ [英] Is there a regex flavor that allows me to count the number of repetitions matched by the * and + operators?

问题描述

有一个正则表达式的味道，让我来算匹配由重复的次数 * 和 + 运营商？我特别想知道，如果可能的.NET平台下。

Is there a regex flavor that allows me to count the number of repetitions matched by the * and + operators? I'd specifically like to know if it's possible under the .NET Platform.

推荐答案

您很幸运，因为实际上.NET正则表达式做到这一点（我认为这是很独特）。基本上在每一个匹配，每个集团商店每捕获的写了。

You're fortunate because in fact .NET regex does this (which I think is quite unique). Essentially in every Match, each Group stores every Captures that was made.

所以，你可以指望有多少次重复的图案由匹配输入：

So you can count how many times a repeatable pattern matched an input by:

• 使其成为一个捕获组
• 在计数多少捕获由该组中的每场比赛都取得了
  • 您可以通过个人的捕获循环太多，如果你想要的！
  • Making it a capturing group
  • Counting how many captures were made by that group in each match
    • You can iterate through individual capture too if you want!

    下面是一个例子：

    Regex r = new Regex(@"\b(hu?a)+\b");
    
    var text = "hahahaha that's funny but not huahuahua more like huahahahuaha";
    foreach (Match m in r.Matches(text)) {
       Console.WriteLine(m + " " + m.Groups[1].Captures.Count);
    }
    

    此照片（因为看到ideone.com ）：

    hahahaha 4
    huahuahua 3
    huahahahuaha 5
    

    API参考

    • <一个href="http://msdn.microsoft.com/en-us/library/system.text.regularex$p$pssions.capturecollection_members%28v=VS.100%29.aspx"><$c$c>CaptureCollection

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