i = i + 1& i ++ [英] Difference Between i = i+1 & i++

问题描述

任何人都可以解决我的困惑在这里是我的代码：

  byte i = 0; 
 
 i ++; 
 System.out.println（i）; 
  

结果： 1

  byte i = 0; 
 
 i = i + 1; 
 System.out.println（i）; 
  

生成编译时错误： 类型不匹配：无法从int转换为byte

当我将它转换为字节时： i = 1）;

p>执行此示例我理解i = i + 1& i ++执行不能同样opearation所以现在我想知道它们之间的确切的差别... !!!

解决方案

最后我找到我的问题（问题）高级理解，所以这里描述它来容易理解其他人！

1> i = i + 1

<在两个或多个变量之间执行，则其返回值的类型取决于以下方程：

返回值类型=（int，VARIABLE的MAXIMUM RANGE -1，MAXIMUM RANGE
OF VARIABLE-N）

此处，返回值类型： int

对于等式（int，byte，byte） 因此int有最大范围..

字节 - > 1字节大小&
int - > 4 byte size

这就是为什么上面的exe不能存储返回值的字节直接它需要 external类型转换 i =（byte）（i + 1）

在java中，每当增量&递减操作执行像这样，那么它的返回值的类型取决于这个方程：

返回值类型=（VARIABLE TYPE，VALUE + 1） / p>

这些方程表示内部类型转换在此情况下执行

必须记住：

case 1 ： / em>

Can anyone solve my confusion here is my code :

byte i = 0;

i++;
System.out.println(i);

Result: 1

byte i = 0;

i = i+1;
System.out.println(i);

Generate compile time error: Type mismatch: cannot convert from int to byte

When I convert that to byte like: i = (byte) (i+1); then happily getting result 1

Performing this example i am understand i = i+1 & i++ perform can't same opearation so now i want to know what is exactally difference between them ...!!!

解决方案

Finally i am found my problems(questions) superior understand so here describe it to understands others easily..!!!

1> i = i + 1

In java whenever any arithmetic operation performs between two or more variables then it's return value's type depends upon like this equation :

RETURN VALUE TYPE = (int, MAXIMUM RANGE OF VARIABLE-1, MAXIMUM RANGE OF VARIABLE-N )

here, Return value type : int

For eqution (int, byte, byte) so int have maximum range..

byte -> 1 byte size & int -> 4 byte size

That's why above exe i can't store that return value in byte directly it's require external type casting i = (byte) (i+1)

2> i++

In java whenever increment & decrement operation perform like these then it's return value's type depends upon this equation:

RETURN VALUE TYPE = (VARIABLE TYPE, VALUE + 1)

these equation denote internal type casting perform in this case

MUST REMEMBER:

case 1: External type cast require if needed

case 2: internal type casting perform automatically

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