如何在init脚本中以特定用户身份运行命令？ [英] How to run a command as a specific user in an init script?

问题描述

我正在编写一个初始化脚本，该脚本应该作为不同于root的用户执行单个命令。这是我目前的做法：

sudo -u username命令

I'm writing an init script which is supposed to execute a single command as a user different than root. This is how I'm doing it currently:
sudo -u username command

这通常在Ubuntu / Debian上正常工作，但是在RHEL上，命令挂起时执行的脚本。

有另一种方法运行命令作为另一个用户？

（请注意，我不能使用lsb init函数，因为它们在RHEL / Centos 5.x上不可用。）

This generally works as expected on Ubuntu/Debian, but on RHEL the script which is executed as the command hangs.
Is there another way to run the command as another user?
(Note that I can't use lsb init functions as they're not available on RHEL/Centos 5.x.)

推荐答案

在RHEL系统上， /etc/rc.d/init.d/functions 脚本旨在提供类似于你要什么。

On RHEL systems, the /etc/rc.d/init.d/functions script is intended to provide similar to what you want. If you source that at the top of your init script, all of it's functions become available.

提供帮助的特定函数是守护进程。如果你打算使用它来启动类似daemon的程序，一个简单的用法是：

The specific function provided to help with this is daemon. If you are intending to use it to start a daemon-like program, a simple usage would be:

daemon --user=username command

如果这对你所需要的太重了，有 runuser （详见 man runuser ）：

If that is too heavy-handed for what you need, there is runuser (see man runuser for full info):

/sbin/runuser -u username -s /bin/bash -c "command(s) to run as user username"

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