如何在Golang字符串中索引字符？ [英] How to index characters in a Golang string?

问题描述

如何获取E输出而不是69？

How to get an "E" output rather than 69?

package main

import "fmt"

func main() {
    fmt.Print("HELLO"[1])
}

Golang有将字符转换为字节的功能吗？

Does Golang have function to convert a char to byte and vice versa?

推荐答案

解释的字符串文字是双引号之间的字符序列，使用单个字符的UTF-8编码（可能是多字节）。在UTF-8中，ASCII字符是单字节，对应于前128个Unicode字符。字符串的行为像字节。 rune是标识Unicode代码点的整数值。因此，

Interpreted string literals are character sequences between double quotes "" using the (possibly multi-byte) UTF-8 encoding of individual characters. In UTF-8, ASCII characters are single-byte corresponding to the first 128 Unicode characters. Strings behave like slices of bytes. A rune is an integer value identifying a Unicode code point. Therefore,

package main

import "fmt"

func main() {
    fmt.Println(string("Hello"[1]))              // ASCII only
    fmt.Println(string([]rune("Hello, 世界")[1])) // UTF-8
    fmt.Println(string([]rune("Hello, 世界")[8])) // UTF-8
}

输出：

e
e
界

查看 Go Programming Language Specification 部分。转换。

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