不能从辅音确定元音 [英] Cannot determine vowels from consonants
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问题描述
使用下面的代码，无论输入的第一个字母是什么，它总是确定为元音：
With the code below, no matter what the first letter of the input is, it is always determined as a vowel:
original = raw_input("Please type in a word: ")
firstLetter = original[0]
print firstLetter
if firstLetter == "a" or "e" or "i" or "o" or "u":
print "vowel"
else:
print "consonant"
事实上，在if语句中布尔值无关紧要，如果是==或！=，它仍然返回vowel。为什么？
In fact, it doesn't matter what the boolean is in the if statement... if it is == or != , it is still return "vowel". Why?
推荐答案
Python不是英语。如果你有一堆表达式或或和在它们之间，每一个必须有自己的意义。注意自己：
Python is not the English language. If you have a bunch of expressions with or or and between them, each one must make sense on its own. Note that on its own:
if "e":
print("something")
将始终打印某些，即使字母不等于e。
will always print something, even if letter doesn't equal "e".
这个：
if letter == "a" or letter == "e" # (...)
或更简洁：
if letter in "aeiouy":
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