辅音和元音斯威夫特 [英] Consonants and Vowels Swift

问题描述

我是Swift的新手，任何人都可以向我解释为什么我会继续遇到这个问题。我正在使用Xcode 6.4，但这里是我的问题，我希望我清除它但我需要我的函数接受大字符串然后返回元组（numVowels，numConsonants）
计算以辅音开头的单词数/元音
返回元组并打印函数调用的结果。
我不需要它来计算字符数，只需要每个单词的第一个字符。我创建一个for循环，将所有内容切换为小写。但现在我被卡住了。

I'm new at Swift, could anyone explain to me why I'm keep getting this problem. I'm using Xcode 6.4, but here is my question I hope I cleared it up but I needed my Function to takes in Large String then returns Tuple(numVowels, numConsonants) Count the number of words that start with consonants/vowels Return the Tuple and print the result of the function call. I did not need for it to count characters, only first character of each word. I create an for loop which will switch everything to lowercase. But now I'm stuck.

func count(string: String) -> (Vowels:Int, Consonants:Int) {
    var Vowels = 0, Consonants = 0
    for character in string {
        switch String(character).lowercaseString {
            case "a","e","i","o","u":
              ++Vowels
            case "b","c","d","e","f","g","h","j","k","l","m","n","p","q","r","s","t","v","w","x","y","z":
            ++Consonants
        default: break
        }

    }
    return (Vowels, Consonants)
}

推荐答案

如果您使用的是swift 2：

if you are using swift 2 :

只需更改此行

for character in string {

到

for character in string.characters {

它只会起作用罚款

count("hello") // (.0 2, .1 3)

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