替换字符串C的单个字符元素 [英] Replace individual character element of a string C

问题描述

我想做一些真正基本的C，但我一直得到分段的错误。所有我想做的是用不同的字母替换一个单词的字母 - 在本例中用l替换l。任何人都可以帮助解释我错了什么？这应该是一个真正基本的问题，我想，我只是不知道为什么它不工作。

I am trying to do something really basic on C but I keep getting a segmentation fault. All I want to do is replace a letter of a word with a different letter- in this example replace the l with a L. Can anyone help explain where I have gone wrong? It should be a really basic problem I think, I just have no idea why its not working.

#include<stdio.h>
#include<stdlib.h>

int main(int argc, char *argv[])
{
    char *string1;

    string1 = "hello";
    printf("string1 %s\n", string1);    

    printf("string1[2] %c\n", string1[2]);
    string1[2] = 'L';
    printf("string1 %s\n", string1);

    return 0;
}

对于我的输出，我得到

string1 hello

string1 [2] l

分段错误

string1 hello
string1[2] l
Segmentation fault

谢谢！

推荐答案

string1 = "hello";
string1[2] = 'L';

您无法更改字符串字面值，它是未定义的行为。尝试此操作：

You can't change string literals, it's undefined behavior. Try this:

char string1[] = "hello";

或也许：

char *string1;
string1 = malloc(6); /* hello + 0-terminator */
strcpy(string1, "hello");

/* Stuff. */

free(string1);

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