Unicode值\uXXXX到Javascript中的字符 [英] Unicode value \uXXXX to Character in Javascript
问题描述
我从来没有这样做,我不知道为什么它输出臭名昭着的
编码字符。任何想法如何输出字符,因为他们应该(ASCII + Unicode)?我认为 \\\A
- \\\Z
应打印 AZ
var c = new Array(F E,D,C,B,A,9,8,7,6,5,4,3,2,1,0)
var n = 0;
var d =;
var o =;
for(var i = 16; i - ;){
for(var j = 16; j-;){
for(var k = 16; k - ;){
for(var l = 16; l - ;){
d = c [i] .toString()
+ c [j] .toString ()
+ c [k] .toString()
+ c [l] .toString();
o + =(++ n +:
+ d +=
+ String.fromCharCode(\\u+ d)
+\\\
< br />);
if(n> = 500){i = j = k = l = 0;} // stop early
}
}
}
}
document.write(o);
解决方案 .fromCharCode
函数接受一个数字,而不是字符串。你不能把一个这样的字符串放在一起,期望解析器做你认为它会做;
您可以改写您的代码,以从十六进制数字中创建一个字符串(不带\u),然后调用
var n = parseInt(hexString,16);
获取值。然后您可以使用 值调用 .fromCharCode()
。
I've never done this before and am not sure why it's outputting the infamous �
encoding character. Any ideas on how to output characters as they should (ASCII+Unicode)? I think \u0041
-\u005A
should print A-Z
in UTF-8, which Firefox is reporting is the page encoding.
var c = new Array("F","E","D","C","B","A",9,8,7,6,5,4,3,2,1,0);
var n = 0;
var d = "";
var o = "";
for (var i=16;i--;){
for (var j=16;j--;){
for (var k=16;k--;){
for (var l=16;l--;){
d = c[i].toString()
+ c[j].toString()
+ c[k].toString()
+ c[l].toString();
o += ( ++n + ": "
+ d + " = "
+ String.fromCharCode("\\u" + d)
+ "\n<br />" );
if(n>=500){i=j=k=l=0;} // stop early
}
}
}
}
document.write(o);
解决方案 The .fromCharCode()
function takes a number, not a string. You can't put together a string like that and expect the parser to do what you think it'll do; that's just not the way the language works.
You could ammend your code to make a string (without the '\u') from your hex number, and call
var n = parseInt(hexString, 16);
to get the value. Then you could call .fromCharCode()
with that value.
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