Javascript:Unicode字符串到十六进制 [英] Javascript: Unicode string to hex
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问题描述
我试图在javascript中将unicode字符串转换为十六进制表示。
这就是我所拥有的:
函数convertFromHex(hex){
var hex = hex.toString(); //强制转换
var str ='';
for(var i = 0; i< hex.length; i + = 2)
str + = String.fromCharCode(parseInt(hex.substr(i,2),16));
return str;
}
函数convertToHex(str){
var hex =''; ($ i = 0; i hex + =''+ str.charCodeAt(i).toString(16);
}
return hex;
}
但是如果unicode字符失败,像中文;
输入:
汉字
输出:
ªo[W
任何想法?这可以在JavaScript中完成吗?
解决方案
请记住, JavaScript代码单元的宽度是16位,因此十六进制字符串的格式为每个代码单元4位数字。
用法:
var str =\\\漢\\\字; //\\\漢\\\字===汉字
alert(str.hexEncode( ).hexDecode());
字符串到十六进制形式:
String.prototype.hexEncode = function(){
var hex,i;
var result =;
for(i = 0; i< this.length; i ++){
hex = this.charCodeAt(i).toString(16);
result + =(000+ hex)。切片(-4);
}
返回结果
}
返回:
String.prototype.hexDecode = function(){
var j;
var hexes = this.ma tch(/。{1,4} / g)|| [];
var back =;
for(j = 0; j back + = String.fromCharCode(parseInt(hexes [j],16));
}
返回;
}
I'm trying to convert a unicode string to a hexadecimal representation in javascript.
This is what I have:
function convertFromHex(hex) {
var hex = hex.toString();//force conversion
var str = '';
for (var i = 0; i < hex.length; i += 2)
str += String.fromCharCode(parseInt(hex.substr(i, 2), 16));
return str;
}
function convertToHex(str) {
var hex = '';
for(var i=0;i<str.length;i++) {
hex += ''+str.charCodeAt(i).toString(16);
}
return hex;
}
But if fails on unicode characters, like chinese;
Input: 漢字
Output: ªo"[W
Any ideas? Can this be done in javascript?
解决方案
Remember that a JavaScript code unit is 16 bits wide. Therefore the hex string form will be 4 digits per code unit.
usage:
var str = "\u6f22\u5b57"; // "\u6f22\u5b57" === "漢字"
alert(str.hexEncode().hexDecode());
String to hex form:
String.prototype.hexEncode = function(){
var hex, i;
var result = "";
for (i=0; i<this.length; i++) {
hex = this.charCodeAt(i).toString(16);
result += ("000"+hex).slice(-4);
}
return result
}
Back again:
String.prototype.hexDecode = function(){
var j;
var hexes = this.match(/.{1,4}/g) || [];
var back = "";
for(j = 0; j<hexes.length; j++) {
back += String.fromCharCode(parseInt(hexes[j], 16));
}
return back;
}
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