Python正则表达式反拉丁1字符编码? [英] Python regex against Latin-1 character encoding?
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问题描述
我有一个包含(我相信)拉丁-1编码的文件。
I have a file which contains (I believe) latin-1 encoding.
但是,我不能匹配正则表达式对这个文件。
However, I cannot match regexes against this file.
如果我的猫文件,它看起来不错:
If I cat the file, it looks fine:
但是,我找不到字符串:
However, I cannot find the string:
In [12]: txt = open("b").read()
In [13]: print txt
<Vw_IncidentPipeline_Report>
In [14]: txt
Out[14]: '\x00 \x00 \x00<\x00V\x00w\x00_\x00I\x00n\x00c\x00i\x00d\x00e\x00n\x00t\x00P\x00i\x00p\x00e\x00l\x00i\x00n\x00e\x00_\x00R\x00e\x00p\x00o\x00r\x00t\x00>\x00\r\x00\n'
In [22]: txt.find("Vw_IncidentPipeline_Report")
Out[22]: -1
In [23]: txt.decode("latin-1")
Out[23]: u'\x00 \x00 \x00<\x00V\x00w\x00_\x00I\x00n\x00c\x00i\x00d\x00e\x00n\x00t\x00P\x00i\x00p\x00e\x00l\x00i\x00n\x00e\x00_\x00R\x00e\x00p\x00o\x00r\x00t\x00>\x00\r\x00\n'
In [25]: txt.decode("utf-16le")
Out[25]: u'\u2000\u2000\u3c00\u5600\u7700\u5f00\u4900\u6e00\u6300\u6900\u6400\u6500\u6e00\u7400\u5000\u6900\u7000\u6500\u6c00\u6900\u6e00\u6500\u5f00\u5200\u6500\u7000\u6f00\u7200\u7400\u3e00\u0d00\u0a00'
如何成功解码字符串,以便在其中找到字符串?
How do I successfully decode the string, so I can find strings within it?
推荐答案
这不是拉丁语-1,它是utf-16大端序:
It's not Latin-1, it's utf-16 big endian:
>>> txt = '\x00 \x00 \x00<\x00V\x00w\x00_\x00I\x00n\x00c\x00i\x00d\x00e\x00n\x00t\x00P\x00i\x00p\x00e\x00l\x00i\x00n\x00e\x00_\x00R\x00e\x00p\x00o\x00r\x00t\x00>\x00\r\x00\n'
>>> txt.decode("utf-16be")
u' <Vw_IncidentPipeline_Report>\r\n'
b $ b
所以,只是解码那种方式,生活幸福之后; - )。
so, just decode that way and live happily ever after;-).
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