正则表达式与拉丁字符 [英] Regex with latin characters

问题描述

我有这个正则表达式：

if (cadena.matches("^[a-zA-Z ]+$")) return true;

它接受从A到Z的小写和大写。也接受空格。

It's accepting from A to Z as lowercase and uppercase. Also accepting spaces.

但这只适用于英语。例如，在加泰罗尼亚语中，我们有'ç'字符。我们还有'á'或'à'等字符。

But this is working just for english. For instance, in Catalan we've the 'ç' character. Also we've characters with 'á', or 'à', etc.

有些谷歌和我找不到任何方法可以做到这一点。

Did some google and I couldn't find any way to do this.

我发现我可以过滤掉UTF-8，但这会接受非真正字母的字符。

I found out that I can filter for UTF-8 but this would accept characters that are not really a letter.

我该如何实现呢？

推荐答案

使用此正则表达式：

[\p{L}\s]+

\p {L} 表示任何Unicode字母。

\p{L} means any Unicode letter.

fiddle.re演示。

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