使用LLVM LibFuzzer时，'fsantize-coverage = edge'中的无效值'edge' [英] invalid value 'edge' in 'fsantize-coverage=edge' when using LLVM LibFuzzer

问题描述

http://llvm.org/docs/LibFuzzer.html
I '现在做一些工作与libfuzzer，但当我做官方玩具的例子。当我运行这个命令：

http://llvm.org/docs/LibFuzzer.html I'm doing some works with libfuzzer now but when I do with the official toy example. when i run this command:

clang++ -fsanitize=address -fsanitize-coverage=edge test-fuzzer.cc Fuzzer*.o

有错误发生

clang: error: invalid value 'edge' in 'fsanitize-coverage=edge'

似乎clang支持这个参数，但我想知道我可以看到什么值是支持...
i安装llvm 3.6通过apt-get与unbuntu14.04 ...

it seems that clang supports this argument but i'm wondering how i can see what value is supported... i installed llvm 3.6 by apt-get with unbuntu14.04...

推荐答案

fsanitize-coverage = 标志的语法已更改， 此提交消息从2015年5月开始。此位与您特别相关：

The syntax of the fsanitize-coverage= flag has been changed, as described in this commit message from May 2015. This bit is particularly relevant to you:

Original semantics of -fsanitize-coverage flag is preserved:
  * -fsanitize-coverage=0 disables the coverage
  * -fsanitize-coverage=1 is a synonym for -fsanitize-coverage=func
  * -fsanitize-coverage=2 is a synonym for -fsanitize-coverage=bb
  * -fsanitize-coverage=3 is a synonym for -fsanitize-coverage=edge
  * -fsanitize-coverage=4 is a synonym for -fsanitize-coverage=edge,indirect-calls

因此，您可以尝试 -fsanitize-coverage = 3 。

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